Question:
On a coordinate plane, a curved line with
minimum values
o (negative 1.56, negative 6)
o (3, 0),
maximum value
o (1.2, 2.9),
crosses the x-axis
o (negative 2.5, 0),
o (0, 0),
o (3, 0),
crosses the y-axis
o (0, 0).
Which interval for the graphed function has a local minimum of 0?
[–3, –2]
[–2, 0]
[1, 2]
[2,3]
Step-by-step explanation:
From the given information, it 'crosses' the x-axis at (3,0), and this is also a minimum. Thus the local minimum is at (3,0), so the answer choice for the interval is [2,3] (not indicated in the posted question, so double check).
<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
Answer: A. 860 583 785 814 010 122 337 198 621 549 034 076 796 495 978 078 433 330 333 153
Answer:
It makes sense at the beginning, but I'm sure that there's a second part??
Step-by-step explanation:
Sorry love
Answer:
BRO YOU GOTTA WRITE A QUESTION
Step-by-step explanation: