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hodyreva [135]
2 years ago
8

If a average person and a trained athlete where to exercise which pule rate would be slow and which pulse rate would be fast?

Chemistry
2 answers:
alexandr1967 [171]2 years ago
6 0
Will i have 2 times plus 7
jekas [21]2 years ago
3 0
The average person would have a higher pulse rate when exercising because their body is not used to it, which makes it have to work harder to maintain that status

the athlete would have a slower pulse rate because their body is acclimated to the exercise and does not need to work as hard to maintain their body
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B. What useful functions do oxidation numbers
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Explanation:

b. What useful functions do oxidation numbers  serve?

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21. a. What is the molar mass of an element?

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7 0
2 years ago
What are the major species in solution when solid ammonium bromate is dissolved in water?
DaniilM [7]
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3 years ago
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SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
Concentration (unknown)
The equation for the reaction is 
NaOH + HBr = NaBr + H2O
The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
                 = 0.0075 moles
NaOH concentration will be 
       = 0.0075 moles × 1000/20
       = 0.375 M

7 0
3 years ago
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