If a average person and a trained athlete where to exercise which pule rate would be slow and which pulse rate would be fast?
2 answers:
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The value of ΔS° for reaction is - 22.2 J/K.mol
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Calculation,
Given value of S°(J/K.mol) for
= 248.5
= 240.5
= 210.6
= 256.2
Formula used:
ΔS° (Reaction) = ∑S°(Product) - ∑S°(Reactant)
ΔS° = (256.2 + 210.6 ) - ( 248.5 + 240.5) = 466.8 - 489 = - 22.2 J/K.mol
The change in stander entropy of reaction is - 22.2 J/K.mol. The negative sign indicates the that entropy of reaction is decreases when reactant converted into product.
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Answer:
26.110 grams of O2 produced.
Explanation:
Calculate the amount of moles in KClO3 by dividing the amount of grams given by the atomic weight of the substance.
To get the atomic weight: K = 39.098, Cl = 35.45, O = 15.999, and there are 3 molecules of Oxygen, so multiply 15.999 by three.
39.098 + 35.45 + (15.999 * 3) = 122.548.
66.7g / 122.548 atomic mass = 0.544 moles.
The ratio of moles of KClO3 to moles of O2 is 2 to 3.
=
Cross multiply to get 1.632 = 2y. Y = 0.816, meaning 0.816 moles of O2 will be produced.
Convert this into grams by multiplying by the atomic weight of O2 (15.999 * 2 = 31.998).
0.816 * 31.998 = 26.110 grams of O2 produced.