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3 years ago

If a average person and a trained athlete where to exercise which pule rate would be slow and which pulse rate would be fast?

Chemistry

2 answers:

alexandr1967 [171]3 years ago

6 0

Will i have 2 times plus 7

jekas [21]3 years ago

3 0

The average person would have a higher pulse rate when exercising because their body is not used to it, which makes it have to work harder to maintain that status

the athlete would have a slower pulse rate because their body is acclimated to the exercise and does not need to work as hard to maintain their body

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The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh

Vinil7 [7]

Answer:

Here's what I get

Explanation:

You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.

A. First dilution

Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.

Use the dilution formula to calculate the new concentration.

$\begin{array}{rcl}c_{1}V_{1} & = & c_{2}V_{2}\\0.01985 \times 10.00 & = & c_{2} \times 50.00\\0.1985 & = & 50.00 c_{2}\\\\c_{2}& = & \dfrac{0.1985}{50.00}\\\\& = & \text{0.003 970 mol/L}\\\end{array}$

B. Second dilution

Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.

$\begin{array}{rcl}c_{2}V_{2} & = & c_{3}V_{3}\\0.003970 \times 10.00 & = & c_{3} \times 50.00\\0.03970 & = & 50.00 c_{3}\\\\c_{3}& = & \dfrac{0.03970}{50.00}\\\\& = & \textbf{0.000 7940 mol/L}\\\end{array}\\\text{The concentration of the final solution is $\boxed{\textbf{0.000 7940 mol/L}}$}$

3. Check:

Compare the final concentration with the original

$\begin{array}{rcl}\dfrac{ c_{3}}{ c_{1}} & = & \dfrac{0.0007940}{0.01985}\\& = & \mathbf{\dfrac{1}{25.00}}\\\end{array}\\\text{The concentration of the final solution is } \boxed{\mathbf{\dfrac{1}{25}}} \text{ that of the original solution}$

7 0

3 years ago

True or false, a neutral atom of Silver has 47 electrons

Tema [17]

Answer:

false

Explanation:

5 0

3 years ago

Read 2 more answers

A chemist working for Udensi industries wants to create a new ink for tattoos and cosmetics. Determine the theoretical yield of

leva [86]

Answer:

35.36 g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

8Fe + S₈ —> 8FeS

Next, we shall determine the mass of Fe that reacted and the mass of FeS produced from the balanced equation. This can be obtained as follow:

Molar mass of Fe = 56 g/mol

Mass of Fe from the balanced equation = 8 × 56 = 448 g

Molar mass of FeS = 56 + 32 = 88 g/mol

Mass of FeS from the balanced equation = 8 × 88 = 704 g

SUMMARY:

From the balanced equation above,

448 g of Fe reacted to produce 704 g of FeS.

Finally, we shall determine the theoretical yield of FeS as follow:

From the balanced equation above,

448 g of Fe reacted to produce 704 g of FeS.

Therefore, 22.5 g of Fe will react to produce = (22.5 × 704)/448 = 35.36 g of FeS.

Thus, the theoretical yield of FeS is 35.36 g

3 0

3 years ago

How many moles of carbon are there in 5 g of carbon?

Umnica [9.8K]

Answer:

0.416666667

Explanation:

number of moles= mass of sample ÷ molar mass

=5÷12

=0.41666667

8 0

3 years ago

How many moles is 573.28 g of AgCl?

g100num [7]

Answer:

4 moles

Explanation:

First, let's find the molar mass of AgCl. The molar mass of Ag is 107.87 and the molar mass of chlorine is 35.45 so the total mass is 107.87 + 35.45 = 143.32 grams per mole. Now all we need to calculate is 573.28 / 143.32 = 4 moles.

7 0

3 years ago

Read 2 more answers