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Gennadij [26K]
3 years ago
9

An atom can be compared to our solar system because: WILL MAKE BRAINLIEST!

Chemistry
1 answer:
Sindrei [870]3 years ago
5 0

Answer:

uh i think its D All of the above

Explanation:

sorry if its wrong

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for number less than 0.1, such as 0.06, the zeros to the right of the decimal point but before the first nonzero digit
qaws [65]

For the number less than 0.1 such as 0.006, the zeroes to the right of the decimal point but before the first non zero digit show the decimal place of the first significant digit.

  • The number that is given as digits is established using significant figures.
  • Any two non-zero digits that are separated by a zero are significant figure.
  • Every zero that is both to the right and left of a non-zero digit and the decimal point is not significant figure.
  • The quantity of significant figures frequently reveals the degree of measurement accuracy. From the first non-zero digits in the figure, we may determine the number of significant figures.

There is only one significant figure in the provided number 0.06. The decimal place of the first digit is indicated by the zeros that appear to the right of the decimal point but before the first non-zero digit.

Learn more about significant figure here:

brainly.com/question/11151926

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6 0
1 year ago
During physical changes ,matter always retains its
svlad2 [7]
During physical changes, matter always retains its chemical properties.
7 0
3 years ago
For the process 2SO2(g) + O2(g) --> 2SO3(g),
CaHeK987 [17]

Answer:

–187.9 J/K

Explanation:

The equation that relates the three quantities is:

\Delta G = \Delta H - T \Delta S

where

\Delta G is the Gibbs free energy

\Delta H is the change in enthalpy of the reaction

T is the absolute temperature

\Delta S is the change in entropy

In this reaction we have:

ΔS = –187.9 J/K

ΔH = –198.4 kJ = -198,400 J

T = 297.0 K

So the Gibbs free energy is

\Delta G=-198,400-(297.0)(-187.9)=254.2 kJ

However, here we are asked to say what is the entropy of the reaction, which is therefore

ΔS = –187.9 J/K

8 0
4 years ago
Copper is commonly mined as an ore with a variable percent composition of copper (II) sulfide. This ore is also sometimes referr
pantera1 [17]

Answer:

m_{CuO}=93.6gCuO

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

CuS+\frac{3}{2} O_2\rightarrow CuO+SO_2

Thus, given the 1.00-kg of 12.5% ore, we can compute the theoretical yield of copper (II) oxide via stoichiometry:

m_{CuO}^{theoretical}=1.00kgCuS*\frac{1000gCuS}{1kgCuS} *\frac{12.5gCuS}{100gCuS} *\frac{1molCuS}{95.6gCuS} *\frac{1molCuO}{1molCuS} *\frac{79.5gCuO}{1molCuO} \\\\m_{CuO}^{theoretical}=103.95gCuO

Whereas the third factor accounts for the percent purity of the covellite. Then, given the percent yield, we can compute the actual yield by:

m_{CuO}=103.95gCuO*0.9\\\\m_{CuO}=93.6gCuO

Regards.

6 0
3 years ago
Balancing Chemical Equations & Identifying Chemical Reactions
Stells [14]
The answer is 17 and a half
3 0
3 years ago
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