<span>The combined Boyle's and Charles' gas law says P1V1/T1 = P2V2/T2 </span>
<span>In this case we have (2.5 atm) (900 ml) / 298 K = (P2) (450 ml) / 336 K -----> </span>
<span>7.55 = 1.34P2 -----> P2 = 7.55 / 1.34 = 5.63 atm</span>
Because it is more dense than the water or tea.
Answer:
The mass of gold in crown is 960.61 g.And the volume of gold is
.
Explanation:
Density is defined as mass of the substance present in unit volume of the substance.
Mass of gold in an alloy of crown= m
Mass of silver in an alloy of crown = M
Volume gold in an alloy of crown= v
Volume of silver in an alloy of crown = V
Density of gold = 
Density of silver = 
Volume of the crown = 

..(1)
Mass of eh crown = 1050 g
..(2)
Solving equation (1) and (2):
m = 960.61 g
M = 89.39 g
Volume of the gold = v = 
Volume of silver = V = 
The mass of gold in crown is 960.61 g.And the volume of gold is
.
To be honest, I can’t really see the question. So please next time just type it out lol
Answer:
mass of HCl = 243.5426 grams
Explanation:
1- we will get the mass of the reacting gold:
volume of gold = length * width * height
volume of gold = 3.2 * 3.8 * 2.8 = 34.048 cm^3 = 34.048 ml<span>
density = mass / volume
Therefore:
mass = density * volume
mass of gold = </span>19.3 * 34.048 = 657.1264 grams
2- we will get the number of moles of the reacting gold:
number of moles = mass / molar mass
number of moles = 657.1264 / 196.96657
number of moles = 3.3362 moles
3- we will get the number of moles of the HCl:
First, we will balanced the given equation. The balanced equation will be as follows:
Au + 2HCl ......> AuCl2 + H2
This means that one mole of Au reacts with 2 moles of HCl.
Therefore 3.3362 moles will react with 2*3.3362 = 6.6724 moles of HCL
4- we will get the mass of the HCl:
From the periodic table:
molar mass of H = 1 gram
molar mass of Cl = 35.5 grams
Therefore:
molar mass of HCl = 1 + 35.5 = 36.5 grams/mole
number of moles = mass / molar mass
Therefore:
mass = number of moles * molar mass
mass of HCl = 6.6724 * 36.5
mass of HCl = 243.5426 grams
Hope this helps :)