Question

If a force of 50 pounds is directed 30° from the horizontal, what vector represents this force?

Answer 1

Answer:

$F_x=43.30\ N$

Step-by-step explanation:

Given that,

Force, F = 50 pounds

It is directed at 30° from the horizontal.

The force will be given by :

$F_x=F\cos\theta\\\\=50\times \cos(30)\\\\=43.30\ N$

So, the required force is 43.30 N.