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Troyanec [42]
2 years ago
5

If a force of 50 pounds is directed 30° from the horizontal, what vector represents this force?

Mathematics
1 answer:
Elan Coil [88]2 years ago
4 0

Answer:

F_x=43.30\ N

Step-by-step explanation:

Given that,

Force, F = 50 pounds

It is directed at 30° from the horizontal.

The force will be given by :

F_x=F\cos\theta\\\\=50\times \cos(30)\\\\=43.30\ N

So, the required force is 43.30 N.

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Answer: 8 (The second option).


Step-by-step explanation:

1. To solve this exercise you draw a line to a point O, this lines will bisect the angle of Z∠60°. Then will obtain two into two right triangles with two angles of 30° at the point Z.

2. The lenght XY will be twice the lengt XO or YO.

3. Let's  calclate XO as following:

sin(30)=\frac{XO}{8}\\XO=4

4. Then, XY is:

XY=2XO\\XY=2*4\\XY=8


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