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2 years ago

Cruising down the street in my 6-4

Chemistry

1 answer:

Doss [256]2 years ago

6 0

Answer:

drug addiction

Explanation:

Wanna take it all back to where it started

Life of the party

Right where my heart at

Soon as what I want come in, I say anything goes

On the road, cool, ridin' 'round with the top down

Nowhere to go to, decide that I'll just ride 'round

She a drug abuser from a broken heart, oh, oh

Got a bad addiction, I been druggin' hard all month long

I'm in that Wraith, I ain't got nothin' but some residue on me

I'm chasin' a check to the morning

I'm in the trenches with smokers and steppers and loners

Somethin' more than one Schedule II on me

Matter fact, just a convicted felon, I'm keepin' my weapon

I'm pourin' more blood on that money

Owe it all to the youngin who feel that he owe the ones

Put addiction 'fore hunger

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Which statement below matches the correct response with the proper reasoning when comparing the volatility of CH2Cl2 with CH2Br2

Nutka1998 [239]

Answer:

b. CH₂Cl₂ is more volatile than CH₂Br₂ because of the large dispersion forces in CH₂Br₂

Explanation:

CH₂Cl₂ is more volatile than CH₂Br₂ (b.p of CH₂Cl₂ = 39,6 °C; b.p of CH₂Br₂ = 96,95°C). Thus, c. and d. are FALSE

Dipole-dipole interactions in CH₂Cl₂ are greater than the dipole-dipole interactions in CH₂Br₂ because Cl is more electronegative that Br (Cl = 3,16; Br = 2,96). But this mean CH₂Cl₂ is less volatile than CH₂Br₂ but it is false.

There are large dispersion forces in CH₂Br₂ because Br has more electrons and protons than Cl. Large disperson forces mean CH₂Br₂ is less volatile than CH₂Cl₂ and it is true.

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3 years ago

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Answer:

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2 years ago

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