increasing the temperature shifts the equilibrium in the direction of the reaction in which heat is absorbed.
Explanation:
The concentration of NO at equilibrium will increase when the reaction takes place at a higher temperature because increasing the temperature shifts the equilibrium in the direction of the reaction in which heat is absorbed.
The reaction is an endothermic reaction.
N₂ + O₂ + heat ⇄ 2NO
According to Le Chatelier's principle, "if any of the conditions of a system in equilibrium is changed the system will adjust itself in order to annul the effect of the change".
- In an endothermic reaction, heat is usually absorbed.
- We see that in the backward reaction, heat is absorbed.
- If the temperature of this reaction is increased, the backward reaction is favored more.
- Since the reactants are combining better, more products NO results.
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Answer:
Protons are a type of subatomic particle with a positive charge
Neutrons are a type of subatomic particle with no charge (they're neutral).
Answer:
C. substances that are used up in a reaction
Explanation:
Substances are combined in a chemical reaction to give rise to other substances. The substances that come together are called REACTANTS while the substances that are produced are called PRODUCTS.
Reactants are used up in the reaction to give rise to new products at the end of the reaction. For example, in the reaction as follows:
6CO2 + 6H2O --> C6H12O6 + 6O2
CO2 (carbon dioxide) and water (H2O) are the REACTANTS of the reaction, which are used up to form glucose and oxygen (products)
Answer:
The correct answer is Option C (E1) and Option B (carbocation).
Explanation:
- Intramolecular immunity idols are considered as that of the formation mechanism with E1 responses or reactivity.
- Reactants with E1 were indeed obligations of both parties, meaning that an E1 reaction was conducted thru all the two stages known as ionization but rather deprotonation. Involves the absence of either an aromatic ring, a carbocation has been generated throughout the ionization solution.
Some other possibilities offered aren't relevant to the procedure outlined. So the above alternative is accurate.
Answer:
The final concentration is 0.288 M (approximately)
Explanation:
Using dilution formula:
C1V1 = C2V2
Where C1 is the initial concentration
C2 is the final concentration
V1 is the initial volume
V2 is the final volume
In the first dilution, C1 = 1.8M,
V1 =71mL, V2 = 218mL from the formula C2 = 1.8 ×71/281
=0.5862M
In the second dilution,
C1 = 0.5862M, V1 = 109mL, V2 = 222 mL (109+113)
C2 = 0.5862 × 109 ÷ 222
= 0.288 M (approximately) assuming volume is additive.
