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omeli [17]
3 years ago
13

Help I have no idea what I'm doing!!

Chemistry
2 answers:
harkovskaia [24]3 years ago
3 0
You have to solve it and color in the numbers i guess? It doesnt show all of the work
lyudmila [28]3 years ago
3 0
1. 605.952 g
2.
3.1.36 molecules
4.0.29 mols
5.0.955 mols
6.5.336 molecules
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M=<br> V=432.6 mL<br> D=8.4 g/ml
Nitella [24]

Answer:

Explanation:

M=D times V

Answer-3,633.84g

Rounded Answer (correct sig figs)- 3600g

6 0
3 years ago
An unknown compound has a percent composition of 52.10% potassium, 15.8% carbon, and 32.1% oxygen. The molar mass of the compoun
lianna [129]
To determine the empirical formula and the molecular formula of the compound, we assume a basis of the compound of 100 g. We do as follows:

       Mass              Moles                     
K    52.10     52.10/39.10 = 1.33         1.33/1.32 ≈ 1
C    15.8       15.8/12         = 1.32         1.32/1.32 ≈ 1
O     32.1      32.1 / 16       =  2.01        2.01/1.32 ≈ 1.5

The empirical formula would most likely be KCO.
The molecular formula would be K2C2O3.
4 0
4 years ago
Read 2 more answers
A scientist discovered a microscopic unicellular organism with no nucleus which of the following correctly describes the organis
boyakko [2]
The correct option is this: THE ORGANISM IS A PROKARYOTES.
There are basically two types of cells, prokaryotic and eukaryotic cells. The prokaryotic cells are primitive cells which contain only a few materials which are not well organised. This type of cells is usually found in microscopic organisms. The cells lack organised nucleus and cell organelles which have membranes.<span />
7 0
3 years ago
Read 2 more answers
A 1500 kg race car accelerates at a rate of about 9M /s2 as to how much force does the engine need to create for this to happen
IgorC [24]

Answer:

13500 N

Explanation:

According to newtons second law of motion

mass m =1500 Kg

a = 9m/s^2

Force F = mass m × acceleration a

F = 1500×9= 13500 N

7 0
3 years ago
Cual es el propósito de la línea escalonada gruesa de la tabla periódica
noname [10]

Separa los metales de los no metales. Agregame como amiga, saludos.

3 0
3 years ago
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