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omeli [17]
2 years ago
13

Help I have no idea what I'm doing!!

Chemistry
2 answers:
harkovskaia [24]2 years ago
3 0
You have to solve it and color in the numbers i guess? It doesnt show all of the work
lyudmila [28]2 years ago
3 0
1. 605.952 g
2.
3.1.36 molecules
4.0.29 mols
5.0.955 mols
6.5.336 molecules
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Find the total number of atoms in a sample of cocaine hydrochloride, c17h22clno4, of mass 23.0 mg .
Nataliya [291]
From the periodic table:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of nitrogen = 14 grams
mass of oxygen = 16 grams
mass of chlorine = 35.5 grams
Therefore,
molar mass of <span>c17h22clno4 = 17(12) + 22(1) + 35.5 + 14 + 4(16) = 339.5 grams

number of moles = mass / molar mass
number of moles = (23*10^-3) / (339.5)
number of moles = 6.77 * 10^-5 moles

number of atoms = number of moles * Avogadro's number
number of atoms = 6.77*10^-5 * 6.022*10^-23
number of atoms = 4.079 * 10^-27 atoms</span>
3 0
3 years ago
1. What pressure would be exerted by 46.0grams of hydrogen gas placed into a 3.00 L container at
dlinn [17]

Answer:

187.34 atm

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.

make P the subject of the equation

P = nRT/V.............. Equation 2

n = mass(m)/molar mass(m')

n = m/m'............... Equation 3

Substitute equation 3 into equation 2

P = (m/m')RT/V............ Equation 4

Given: m = 46 g, T = 25°C = (25+273) = 298 K, V = 3.00 L

Constant: m' = 2 g/mol, R = 0.082 atmL/K.mol

Substitute these values into equation 4

P = (46/2)(0.082×298)/3

P = (23×0.082×298)/3

P = 187.34 atm

3 0
3 years ago
I’m not sure on this!!!
Talja [164]

Answer:

-14

Explanation:

H=-6

G=7

therefore,

=7(H)+4(G)

=7(-6)+4(7)

=-42+28

=-14

8 0
2 years ago
Read 2 more answers
A sample of an unknown solid is found to have a volume of 24.3 cm3 and a mass of
blondinia [14]
<h2>Answer:  8.93 g/cm³ </h2>

<h3>Explanation: </h3>

Density = mass ÷ volume  

           = 217.0 g ÷ 24.3 cm³  

           = 8.93 g/cm³

∴ the unknown sample of mass 217.0 grams and volume of 24.3 cm³ has a density of 8.93 g/cm³.

5 0
2 years ago
Calculate the ph of the solution 0.2M Mg(OH)2
Kipish [7]

Mg(OH)2 is base

Oh = 0.2 x 2 = .4

Poh = - Log (.4)

= .3979

Ph + Poh = 14

Ph = 14 - .3979

= 13.60

6 0
3 years ago
Read 2 more answers
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