The answer is A. A mole of Cu has the same number of atoms as a mole of He atoms
Answer:
Mass = 1.33 g
Explanation:
Given data:
Mass of argon required = ?
Volume of bulb = 0.745 L
Temperature and pressure = standard
Solution:
We will calculate the number of moles of argon first.
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
By putting values,
1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K
0.745 atm. L = n × 22.43 atm.L/mol
n = 0.745 atm. L / 22.43 atm.L/mol
n = 0.0332 mol
Mass of argon:
Mass = number of moles × molar mass
Mass = 0.0332 mol × 39.95 g/mol
Mass = 1.33 g
0.88qt
Explanation:
Given parameters:
Density of ebony wood = 1.174g/ml
Mass of wood = 2.1549lb
Unknown:
Volume of the wood in quarts = ?
Solution:
Density is defined as the mass per unit volume of a substance.
Mass is the quantity of matter the wood contains.
Volume is the space it occupies.
To solve this problem, convert the mass form pounds into grams and plug into the density equation to find volume.
Then convert the volume from mL to quarts.
Density =
Volume =
1 pound = 453.592g
2.1549 lb = 2.1549 x 453.592 = 977.5g
Volume = = 832.6mL
1 quart = 946.353mL
Therefore 832.6mL x = 0.88qt
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Density brainly.com/question/8441651
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Answer:
Partial pressure of CO₂ is 406.9 mmHg
Explanation:
To solve the question we should apply the concept of the mole fraction.
Mole fraction = Moles of gas / Total moles
We have the total moles of the mixture, if we have the moles for each gas inside. (3.63 moles of O₂, 1.49 moles of N₂ and 4.49 moles of CO₂)
Total moles = 3.63 mol O₂ + 1.49 mol N₂ + 4.49 mol CO₂ = 9.61 moles
To determiine the partial pressure of CO₂ we apply
Mole fraction of CO₂ → mol of CO₂ / Total moles = P. pressure CO₂ / Total P
Partial pressure of CO₂ = (mol of CO₂ / Total moles) . Total pressure
We replace values: (4.49 moles / 9.61 moles) . 871 mmHg = 406.9 mmHg