Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g
Answer:
I use to do it so my swings can mainly be quicker
Explanation:
When fluorine gas reacts with calcium metal at high temperatures then it results into the formation of calcium fluoride.
Since, calcium has 2 extra electrons as its electronic distribution is 2, 8, 8, 2. Whereas each fluorine atom needs one electron to complete its octet.
Therefore, the chemical reaction equation will be as follows.
I'm pretty sure its the first one
Explanation:
Answer:
B. 288. G
Explanation:
Moles of Al :
Given, Mass of Al = 20.4 g
Molar mass of Al = 26.9815 g/mol
The formula for the calculation of moles is shown below:
Thus,
The reaction between Al and I is shown below as:
2Al + 3I₂ ⇒ 2AlI₃
2 moles of aluminium react with 3 moles of iodine
1 mole of aluminium react with 3/2 moles of iodine
0.7561 moles of aluminium react with (3/2)*0.7561 moles of iodine
Moles of Iodine = 1.13415 moles
Molar mass of NaOH = 253.8089 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass of Iodine = 288 g