Middle option.
<span>(x + 1 ≤ 1) ∩ (x + 1 ≥ 1)
If you work both sides separately you get
</span>(x ≤ 0) ∩ (x ≥ 0)
<span>
which reduces nicely to
</span><span>{x | x = 0}</span>
Answer:
100% all of them
Step-by-step explanation:
he bought (p) oranges so if 1% are bad they are still there, so there are still 100% of the oranges remaining because he hasn't aten any or disposed of any.
Answer:
Either B or D.
Step-by-step explanation:
I consider both options valid. It all depends on how the employer is keeping track of time, ie if the pay "ticks" every 60 minutes, or an employee is allowed to clock in half hours.
Will I be able to work 30 and a half hour for example? If I'm allowed to, D.
If I have to work multiple of 60 minutes, B.
