Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.
Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.
Answer:
The use of symbols to represent ideas or qualities.
Answer:
The chart is linear, the graph is not.
Step-by-step explanation:
Because the graph is curved and not straight, it is non-linear. You can also tell that this is non-linear because the rate of change, or slope, is inconsistent. The chart is linear because it has a consistent slope. I hope this helps, have a nice day. :-)
The right answer for the question that is being asked and shown above is that: "B. The overlap is high because the difference in the means is small compared to either MAD" The <span>statement that best describes the overlap in the distribution of the two data sets is that </span><span>B. The overlap is high because the difference in the means is small compared to either MAD</span>
Answer:
I understand there is a typo, so Belly and Billy are the same person. His age is represented as B, and Suzy's as S.
S = 19
B = 9
Step-by-step explanation:
Suzy is ten years older than Belly:
(1) S = B + 10
the next year she will be twice as old as Billy
(2) S + 1 = 2 (B + 1)
solving the system of equation (1) and (2):
Making (2) - (1):
1 = 2 (B + 1) - B - 10 => 1 = 2 B + 2 - B - 10 => 1 = B - 8 => B = 9
replacing in (1) S = 19
