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ale4655 [162]
3 years ago
5

John is going to back to that is 18 inches deep he notices that it takes two minutes to fill the bathtub with 3 inches of water

he estimates it will take 10 more minutes for the water to reach the top of the tub if he continues at the same rate is he correct
Mathematics
1 answer:
algol133 years ago
4 0
Yes,

Every 2 minutes = 3 inches of water, so that means every minute = 1.5 inches of water.

So in 10 minutes:

10*(1.5) = 15 inches of water.

So in 10 minutes the tub will fill an additional 15 inches of water which is exactly how much you need to fill up the remaining tub (3+15 = 18)
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I need to know the surface area of this shape
Sophie [7]
The area is the area of 2 pairs of congruent triangles and one rectangle. Use the formulas for the areas of these figures, then add results.

Front triangle area (A = (1/2)bh)
.. = (1/2)(16 m)*(25 m) = 200 m^2

Right side triangle
.. = (1/2)(22 m)*(24 m) = 264 m^2

Base (A = lw)
.. = (16 m)*(22 m) = 352 m^2

Total area
.. 2*front triangle +2*side triangle +base
.. = 2*200 m^2 +2*264 m^2 +352 m^2
.. = 1280 m^2
4 0
3 years ago
Nina knows that the average of the x-intercepts represents the line of symmetry for a quadratic function through the x-axis. Whi
Dafna1 [17]
To get the x-intercepts of the function, f(x) = 4x2 – 24x + 20

It has to be equated to zero and the values of x are the x-intercepts. So,
4x2 – 24x + 20 = 0
The resulting equation is a quadratic equation which can be solved by different methods. The solution is
x = 5, 1
The average therefore is:
(1+5/)2 = 3

6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!! will give brainliest!!!!
Nataly_w [17]

Answer: A Good luck :)

3 0
3 years ago
Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra
katen-ka-za [31]

You made a mistake with the probability p_{j}, which should be p_{i} in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer j, is given by:

(1) \frac{p_{j} }{1-d_{i}p_{i}  } , if j \neq i, and

(2) \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  } , if j = i.

so we can say:

A is the event that you search drawer i and find nothing,

B is the event that you search drawer i and find the paper,

C_{k}  is the event that the paper is in drawer k, k = 1, ..., n.

this gives us:

P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}

P(A) = 1 - P(B) = 1 - d_{i} p_{i}

Solution to Part (1):

if j \neq i, then P(A \cap C_{j} ) = P(C_{j} ),

this means that

P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)}  = \frac{P(C_{j} )}{P(A)}  = \frac{p_{j} }{1-d_{i}p_{i}  }

as needed so part one is solved.

Solution to Part(2):

so we have now that if j = i, we get that:

P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}

remember that:

P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}

this implies that:

P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )

so we just need to combine the above relations to get:

P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  }

as needed so part two is solved.

8 0
4 years ago
How do I solve this?
algol [13]
I think the answer is (C)
4 0
3 years ago
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