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2 years ago

What are the two groups the animal kingdom is divided into?

Chemistry

1 answer:

Talja [164]2 years ago

8 0

Answer:

Taking the animal kingdom as an example, we can see that it is split into two clear groups: Invertebrates - animals without a backbone. Vertebrates - animals with a backbone.

Explanation:

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HELP ME PLEASEE!!!! BRAINLIEST FOR CORRECT ANSWER NO COPY AND PASTE. CLICK ON THE IMAGE

madreJ [45]

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The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside. ... The only way to use energy is to transform energy from one form to another.

3 0

2 years ago

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SOMEONE PLS HELP

Gekata [30.6K]

Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we're finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

100.7 kPa = 100,700 Pa

95.1 kPa = 95,100 Pa

We have

$V_2 = \frac{100700 \times 439}{95100} = \frac{44207300}{95100} \\ = 464.8506...$

We have the final answer as

Hope this helps you

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2 years ago

A non metal which is good conductor of electricity

Neporo4naja [7]

The non metals good conductivity any to conduct electric city any time because the metals when we keep into any switch board while we touch we will get shock but non metals not like that

7 0

3 years ago

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5.36 liters of nitrogen gas are at STP. What would be the new volume if we increased the moles from 3.5 moles to 6.0 moles?

Aleksandr [31]

Answer:

$V_2=9.20L$

Explanation:

Hello there!

In this case, according to the given STP (standard pressure and temperature), it is possible for us to realize that the equation to use here is the Avogadro's law as a directly proportional relationship between moles and volume:

$\frac{V_2}{n_2}= \frac{V_1}{n_1}$

In such a way, given the initial volume and both initial and final moles, we can easily compute the final volume as shown below:

$V_2= \frac{V_1n_2}{n_1} \\\\V_2=\frac{5.36L*6.0mol}{3.5mol}\\\\V_2=9.20L$

Best regards!

3 0

2 years ago

1.)What is the molarity of a solution that contains 55.0 grams of Na2SO4 in 250 milliliters of solution? (The mass of one mole o

Maurinko [17]

1)1.549=1.55M

2)may include all of these characteristics

3)stronger the acid

4)lower the concentration of H3O+ ions

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2 years ago