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A reaction has activation energy of 85kjper mol. What is the effect on the rate of raising the temperature from 20degree to 30 d

DENIUS [597]

Answer: The rate increases 3 times on raising the temperature from 20degree to 30 degree

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

$ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]$

where $k_2$ = rate constant at temp $T_2$

$k_1$ = rate constant at temp $T_1$

$E_a$ = activation energy

R= gas constant

$T_1$ = temperature = $20^0C=(20+273)K=293K$

$T_2$ = temperature = $30^0C=(30+273)K=303K$

$ln \frac{k_{2}}{k_{1}} = \frac{-85\times 1000J/mol}{8.314J/Kmol}[\frac{1}{303} - \frac{1}{293}]$

$ln \frac{k_{2}}{k_{1}}=1.15$

$\frac{k_{2}}{k_{1}}=3$

Thus rate increases 3 times on raising the temperature from 20degree to 30 degree

3 0

3 years ago

An atom (not a hydrogen atom) absorbs a photon whose associated wavelength is 300 nm and then immediately emits photon whose ass

KIM [24]

Answer:

The net energy is 2.196 eV

Explanation:

Basically, the energy of an atom increases when it absorbs a photon. In addition, the wavelength of the emitted photon is longer such that the atom absorbed a net energy in the process.

Using:

ΔE = h*c*(1/λ $_{1}$ - 1/λ $_{2}$ )

where:

ΔE is the net energy in eV (electron-volt). 1 eV is equivalent to 1.602* $10^{-19}$ J.

h = 4.135* $10^{-15}$ eVs

c = 3* $10^{8}$ m/s

λ $_{1}$ = 300 nm = 300* $10^{-9}$ m

λ $_{2}$ = 640 nm = 640* $10^{-9}$ m

Thus:

ΔE = 4.135* $10^{-15}$ eVs*3* $10^{8}$ m/s*( $\frac{1}{300*10^{-9}m } }-\frac{1}{640*10^{-9}m }$ )

ΔE = 4.135* $10^{-15}$ *3* $10^{8}$ *1.77* $10^{6}$ eV = 2.196 eV

6 0

3 years ago

3. What is the formula for the compound formed from the magnesium ion and nitrate?

bija089 [108]

Answer:

D.) Mg(NO₃)₂

Explanation:

Since magnesium (Mg) is a metal and nitrate (NO₃) is a polyatomic anion, they would combine to form an ionic compound. Magnesium would form the cation Mg²⁺ because it generally has 2 valence electrons. Nitrate always has a -1 charge.

In order for the overall compound to be neutral (have a charge of 0), there must be one Mg²⁺ and two NO₃⁻ ions in the compound (+2 + (-1) + (-1) = 0).

Therefore, the formula for the compound formed is Mg(NO₃)₂.

8 0

2 years ago

Enter a molecular equation for the gas-evolution reaction that occurs when aqueous hydroiodic acid and aqueous potassium sulfite

Katen [24]

Answer:

2HI + K2SO3=>2KI+H2SO3

Explanation:When aqueous hydroiodic acid and aqueous potassium sulfite are mixed the products obtained are potassium iodide and sulfurous acid.Both reactants are ionic compounds and they undergo double replacement reaction.In a double replacement reaction the parts of the ionic compounds are changed.The product is obtained by combinig cation of one compound with anion of other compound.so in above reaction sulfurous acid is obtained which is in gaseous form and potassium iodide is an ionic compound.

3 0

3 years ago

1. Ionization energy is the energy needed to remove an electron from an atom. We can use the periodic table to predict ionizatio

just olya [345]

Ionization energy increases from left to right because the left wants to lose elctrons and the right wants to gain electron

As you go a group it is easier lose lose because the electrons are farther away from the nucleus and there is less attraction from the positive charges.

It should be 3p3. the p level can hold 6 electrons

Rubidium group 1, 1 valence electrons very reactive

Mg2,2 very reactive

Al 3, 3 reactive

6 0

3 years ago