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Naily [24]
3 years ago
13

∵what are two ways that plants compete with one another?∴≠≈±⇄⇄

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
7 0
They compete with sunlight and soil. i think and maybe even water.
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If you have a 12.0 gram steel ball at sea level and then take it up to mt. Fuji what will change?
andrey2020 [161]
The air pressure. the air pressure increases as the altitude an object is at increases.
8 0
3 years ago
The atom in a sample of an element must contain nuclei with the same number of?
slava [35]
Hey there! 

Answer: Protons 

The atom in a sample of an element must contain nuclei with the same number of protons. If the protons change in number, then the element will modify as well. 

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7 0
3 years ago
chlorine has two naturally occurring isotopes, Cl-35 and Cl-37. The atomic mass of chlorine is 35.45. Which of these two isotope
Sliva [168]
Cl-35, as the atomic mass of Chlorine (35.45) is closer to the number 35 than to the number 37. A higher abundance of CL-35 isotope would have caused the atomic number (which is an average of the values of all isotopes of a substances taking relative abundance into consideration) to decrease from 36, which would appear to be the average.
5 0
3 years ago
To answer this question, you may need access to the periodic table of elements.
OleMash [197]

Answer:

b.) Br and Br

Explanation:

A covalent bond occurs when electrons are shared between two atoms causing them to form a bond.

A "pure" covalent bond refers to a nonpolar covalent bond. In these bonds, the electrons are shared equally between two atoms as a result of the absence of an (or very small) electronegativity difference. The purest covalent bond would therefore be between two atoms of the same electronegativity. Two bromines (Br) have the same electronegativity, thus making it the purest covalent bond.

Polar covalent bonds occur when electrons are shared unequally between two atoms. There is a larger electronegativity difference between the two atoms, but not large enough to classify the bonds as ionic. In this case, a.) and c.) are polar covalent bonds and d.) is an ionic bond.

7 0
1 year ago
4. Find the pH at each of the following points in the titration of 25 mL of 0.3 M HF with 0.3 M NaOH. The Ka value is 6.6x10-4 a
yawa3891 [41]

Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

HF+H2O⇌H3O++F−HF+H2O⇌H3O++F−

Initial0.3 M-0 M0 MChange- X-+ X+XEquilibrium0.3 - X-X MX M

Writing the information from the ICE Table in Equation form yields

6.6×10−4=x20.3−x6.6×10−4=x20.3−x

Manipulating the equation to get everything on one side yields

0=x2+6.6×10−4x−1.98×10−40=x2+6.6×10−4x−1.98×10−4

Now this information is plugged into the quadratic formula to give

x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)2

The quadratic formula yields that x=0.013745 and x=-0.014405

However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

6 0
3 years ago
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