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earnstyle [38]
3 years ago
10

Calculate the equilibrium constant K for the following reaction: H2(g) +

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

192.9

Explanation:

From the question,

Ke = [HCL]²/[H₂][CL₂].......................... Equation 1

Where Ke = Equilibrium constant.

Given: [HCL] = 0.0625 M, [H₂] = 0.0045 M, [CL₂] = 0.0045 M

Substitute these values into equation 1

Ke = (0.0625)²/(0.0045)(0.0045)

ke = (3.90625×10⁻³)/(2.025×10⁻⁵)

ke = 1.929×10²

ke = 192.9

Hence the equilibrium constant of the system = 192.9

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Answer:

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Explanation:

Because it mixes in with the earth making the earth more suitable for gardening and/or farming.

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Drops of a clear liquid are added to a red liquid. As the drops are added, the red liquid becomes orange, then yellow
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4 years ago
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Which of these form an ionic bond
zhenek [66]

Answer:

the second 1

Explanation:

7 0
3 years ago
What is the molariity of a 50.0 mL aqueous solution containing 10.0 grams of hydrogen peroxide, H2O2?
daser333 [38]

Answer:

6 mol/L

Explanation:

You should know or have the equation to solve for Molarity which is;

M = n/v          (M: Molarity) (n: moles of solute) (v: Liters of solute)

You can start off differently but I would start by converting the mL to L. This is your "v" value.

50.0 mL/ 1000 mL = <em>0.05 L</em>

Now, you have to convert grams to moles in order to solve for molarity (M).

1.) On the periodic table find the molecular weights of H and O.

H= 1.01 g/mol         O= 16.00 g/mol

2.) Multiply them and then add them together to have their combined molecular weights. (You have to multiply by 2 because of their equation; H2O2).

2(1.01) + 2(16.00)= 34.02 g/mol

3.) Now, you're going to use the "picket fence method" or whichever your teacher taught you to convert from grams to moles. This will be your "n" value. (I cannot show it on here without it looking weird, so my sincere apologies.)

10.0 g/ 34.02 g = <em>0.2939 mol</em>

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4.)You are now going to plug in your answers into the equation for Molarity.

M= 0.2939 mol / 0.05 L = <em>5.878 mol/L</em>

5.) I am sure your professor might be a stickler so for sig figs sake when you multiply or divide use the smallest amount of sig figs you see which is 1. Round 5.878 to 6 mol/L

Sorry this explanation is very long let me know if you need a better more written out explanation.

4 0
4 years ago
Suppose a solution is described as concentrated. Which of the following statements can be concluded? Select the correct answer b
Novosadov [1.4K]

Answer:

  • last option: none of<u> the above.</u>

Explanation:

Describing a solution as<em> concentrated</em> tells that the solution has a relative large concentration, but it is a qualitative description, not a quantitative one, so this does not tell really how concentrated the solution is. This is, the term concentrated is a kind of vague; it just lets you know that the solution is not very diluted, but, as said initially, that there is a relative large amount (concentration) of solute.

One conclusion, of course, is that <u>the solute is soluble</u>: else the solution were not concentrated.

On the other hand, the terms saturated and <em>supersaturated</em> to define a solution are specific.

A saturated solution has all the solute that certain amount of solvent can contain, at a given temperature. A <u>supersaturated solution has more solute dissolved than the saturated solution</u> at the same temperature; superstaturation is a very unstable condition.

From above, there is no way that you can conclude whether a solution is supersaturated or not from the statement that a solution is concentrated, so the answer is<u> none of the above</u>.

5 0
3 years ago
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