Answer:
3
Step-by-step explanation:
because if you are doing negatives it is kinda like subtracting

Answer:
Step-by-step explanation:
2 1/2 + x = 5 1/3 Change the mixed numbers to improper fractions
5/2 + x = 16/3 The lowest common multiple is 6. Multiply by 6
5*3 + 6x = 16*2
15 + 6x = 32 Subtract 15 from both sides.
6x = 32 - 15
6x = 17 Divide by 6
6x/6 = 17/6
x = 2 5/6
Check
5/2 + 17/6 = 16/3
15/6 + 17/6 = 32/6
32/6 = 32/6 The question checks.
Every 10 minutes of reading my book, I read 20 pages each. // part B you read 0.5 minutes per page
Answer:
If you add 690 ml of water you will obtain 1.690 liter of 70% alcohol. Of course if you halve the amounts, e.g. 0.5 liter 75% alcohol and 345 ml of water, you will also obtain 45% alcohol solution.
This is the easiest way to solve this problem:
Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __
For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations
For the next two do the same process as the one above.
If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations
If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.
<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>
10*9*9*9 = 7290 combinations