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gayaneshka [121]
3 years ago
7

4

Chemistry
1 answer:
Helen [10]3 years ago
8 0

Answer:

it will first star out slow them become fast by mass and speed

Explanation:

speed and mass = fast

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Which of the changes listed below would shift this reaction to the right?
nasty-shy [4]

Answer:

D: Increase of pressure

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3 years ago
What is the mathematical equation used when solving calorimetry problems? What does each variable in the equation represent?
liubo4ka [24]

Answer : The mathematical equation used when solving calorimetry problems is:

q=m\times c\times \Delta T}

Explanation :

Calorimetry : It is determining the changes in the energy of a system by measuring the heat transferred with surroundings.

Formula used :

q=m\times c\times \Delta T}

where,

c = specific heat capacity  of calorimeter

m = mass of a substance

q = heat required

\Delta T = change in temperature of substance

7 0
3 years ago
Lavar el arroz y escurrirle el agua es un ejemplo de mezcla....
Tresset [83]

Answer:

me no oblo espenul

Explanation:

4 0
3 years ago
Please help with whatever this is and go in number order
Alenkinab [10]
1.a- sodium(Na) b-nickel(Ni) c-iron (Fe)
6 0
3 years ago
Given the following data, determine the order of reaction with respect to H2.
alex41 [277]

Answer:

First-order with respect to hydrogen.

Explanation:

Hello!

In this case, considering that the rate law of this reaction can be expressed via:

r=k*p_{H_2}^m*p_{ICl}^n

If we want to know m, the order of reaction with respect to hydrogen, we need to relate the experiments 1 and 3 in order to get rid of the pressure of ICl:

\frac{r_1}{r_3} =\frac{k*p_{H_2,1}^m*p_{ICl,1}^n}{k*p_{H_2,3}^m*p_{ICl,3}^n}

Thus, we plug in the given rates, and pressures to get:

\frac{1.34}{0.266} =\frac{k*250^m*325^n}{k*50^m*325^n}

So we can cancel wout k and 325^n:

\frac{1.34}{0.266} =\frac{250^m}{50^m}

Next we solve for m, the order of reaction with respect to hydrogen:

5.04 =5^m\\\\log(5.04)=m*log(5)\\\\m=\frac{log(5.04)}{log(5)} \\\\m=1.0

It means it is first-order with respect to hydrogen.

Regards!

7 0
3 years ago
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