For the following reaction, 25.4 grams of sulfur dioxide are allowed to react with 11.6 grams of water . sulfur dioxide(g) water
1 answer:
Answer:
The maximum mass of sulfurous acid that can be formed is 32.54 grams.
Explanation:
The balanced reaction is:
SO₂ + H₂O → H₂SO₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- SO₂: 1 mole
- H₂O: 1 mole
- H₂SO3: 1 mole
Being the molar masses of each compound:
- SO₂: 64 g/mole
- H₂O: 18 g/mole
- H₂SO₃: 82 g/mole
Then, by stoichiometry the following quantities of mass participate in the reaction:
- SO₂: 1 mole* 64 g/mole= 64 g
- H₂O: 1 mole* 18 g/mole= 18 g
- H₂SO₃: 1 mole* 82 g/mole=82 g
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
To determine the limiting reagent, you can use a simple rule of three as follows: If 18 grams of water react with 64 grams of sulfur dioxide, how much mass of sulfur dioxide does 11.6 grams of water react with?
mass of sulfur dioxide= 41.24 grams
But 41.24 grams of sulfur dioxide are not available, 25.4 grams are available. Since you have less mass than you need to react with 11.6 grams of water, sulfur dioxide will be the limiting reagent.
Then you can apply the following rule of three: if by reaction stoichiometry 64 grams of sulfur dioxide produce 82 grams of sulfurous acid, 25.4 grams of sulfur dioxide, how much mass of sulfurous acid will it produce?
mass of sulfurous acid= 32.54 grams
<u><em>The maximum mass of sulfurous acid that can be formed is 32.54 grams.</em></u>
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Answer: The chemical equation for the formation one mole of from its elements in their standard states is
Explanation:
The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.
The chemical equation for the formation one mole of from its elements in their standard states is:
where (s) represents solid state and (g) represents gaseous state.
The highlighted atoms have sp2 - sp3 hybridization. The highlighted atoms are carbon and nitrogen as shown.
The structure of Xanthine is shown in the image attached to this answer. The indicated atoms are Carbon and nitrogen as shown. Let us remember that hybridization has to do with the mixing of atomic orbitals to form appropriate hybrid orbitals that are suitable for overlap with orbitals of other atoms.
The highlighted carbon atom is sp2 hybridized because it has a carbon nitrogen double bond while the highlighted nitrogen atom is sp3 hybridized. Therefore, the highlighted atoms have sp2 - sp3 hybridization.
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