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Norma-Jean [14]

3 years ago

9

stockbroker allocated \$100,000 to an account earning per year compounded continuously. If no withdrawals are made, how much was

in the account at the end of four years? Round the answer to nearest dollar.

1 answer:

notka56 [123]3 years ago

4 0

Answer:

The range is also the whole of R

Step-by-step explanation:

You might be interested in

You are offered an item of $17.85 if the sellers states he normally sets the same item for $19.95 what percentage discount it he

nadezda [96]

Answer:

Discount percentage = 10.5% (Approx)

Therefore the discount is seller offering you is 10.5 % .

Step-by-step explanation:

Discount = Marked price - Selling price

As given

You are offered an item for $17.85. If the seller states he normally sells the same item for $19.95 .

Here

Marked price = $19.95

Selling price = $17.85

Discount = 19.95 - 17.85

= $2.1

$\frac{2.1 x 100}{19.95}$

$\frac{210}{19.95}$

Discount percentage = 10.5% (Approx)

Therefore the discount is seller offering you is 10.5 % .

6 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0

3 years ago

..........................

QveST [7]

Answer:

x = 0.954

Step-by-step explanation:

We apply pythagorean to find x

(4-x)² = 1.2² + 2.8²

(4-x)² = 9.28

✓(4-x)² = ✓(9.28)²

4 - x = 3.046

- x = 3.046 - 4

- x = -0.954

x = 0.954

(Please heart and rate if you find it helpful, it's a motivation for me to help more people)

7 0

3 years ago

The hypotenuse of a 45 degrees -45 degrees -90 degrees triangle measures 10 root of 5 in.

juin [17]

Answer:

$5\sqrt{10}\ in$

Step-by-step explanation:

<u><em>The question is </em></u>

Find the measure of the legs

we know that

In a 45 degrees -45 degrees -90 degrees triangle, the measure of the legs are equal

Let

a ----> the measure of one leg

Applying the Pythagorean Theorem

$(10\sqrt{5})^2=a^2+a^2$

solve for a

$500=2a^2$

Divide by 2 both sides

$a^2=250$

$a=\sqrt{250}\ in$

Simplify

$a=5\sqrt{10}\ in$

3 0

3 years ago

(brainiest)Which letter would be the most meaningful variable for this problem situation?

dexar [7]

Answer:

options B

Step-by-step explanation:

because its refer to height it's denoted by (h)

7 0

3 years ago