Hello,
7) A∪C={1,2,3,4,5,7,9}
8) A∩B={2,4}
C'= complement of C ={2,4,6}
9) A∪B∩C'={1,2,3,4,6,8}∩{2,4,6}={2,4,6}
10) A∪(B∩C')={1,2,3,4}∩{2,4,6}={1,2,3,4,6}
Are you blind?
Answer:
15
Step-by-step explanation:
Square root of 5=√5
Square of the square root=(√5)^2
=5
Square root of 3=√3
Square of the square root=(√3)^2
=3
So (square root of 5)^2×(square root of 3)^2
5×3
15
Therefore the final answer is 15
Answer:
Use Distance Formula
Step-by-step explanation:
You can find the distance between two points by using the distance formula which by definition is 
For example take question 3. Plug your point values in to find the distance
Point 1 is (-1, 8)
Point 2 is (-3, -2)
You equation would look like:

This simplifies to 
=
=
=
=
That is the distance between the points (-1, 8) and (-3, -2)