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inna [77]
3 years ago
11

Rewrite `10^{32}\ \/ \ 10^{6}\ `using a single exponent.

Mathematics
1 answer:
IrinaVladis [17]3 years ago
8 0

Answer:

10^38

Step-by-step explanation: :)

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What are the zeros of the quadratic function f(x) = 6x^2 + 12x - 7?
Sergeeva-Olga [200]

Answer:

-12 + √(144- 4(-42)/12

-12 + √312/12

-12 + 17.6 / 12

= +.47 and -.47

4 0
3 years ago
Find the dimensions of an American football field. The length is 200 ft more than the width, and the perimeter is 1,040 ft. Find
natka813 [3]

Answer:

The width of the football field is 160 feet.

The length of the football field is 360 feet.

Step-by-step explanation:

Let w represent width of the football field.

We have been given that the length is 200 ft more than the width, so the length of the field would be w+200.

We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

2(w+w+200)=1040

Let us solve for w.

2(2w+200)=1040

4w+400=1040

4w+400-400=1040-400

4w=640

\frac{4w}{4}=\frac{640}{4}

w=160

Therefore, the width of the football field is 160 feet.

Upon substituting w=160 in expression w+200, we will get length of field as:

w+200\Rightarrow 160+200=360

Therefore, the length of the football field is 360 feet.

7 0
3 years ago
Round to the nearest thousandth.<br> -49.5176
Oliga [24]

Answer:

-49.518

This should suffice.

7 0
3 years ago
Read 2 more answers
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
What are the dimensions of the product?
Oksi-84 [34.3K]

Answer:

<h2>2 x 2</h2>

Step-by-step explanation:

Dimensions: m x n

m = number of rows

n = number of columns

When multiplying two matrices:

m x n *  n x k = m x k

MATIX 1:

m = number of rows

n = number of columns

MATRIX 2:

n = number of rows

k = number of columns

RESULTING MATIX:

m = number of rows

k = number of columns

2 x 3 * 3 x 2 = 2 x 2

8 0
3 years ago
Read 2 more answers
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