212 + 28% = <span>271.36</span>
<span>Hope it helps! :D</span>
I think the answer is (a)
D(t)=-16t²+32t+88
a] Maximum height
At maximum height d'(t)=0
from d(t);
d'(t)=-32t+32=0
thus
t=1
hence the maximum height will be:
d(t)=-16t²+32t+88
d(1)=-16(1)^2+32(1)+88
d(1)=104 ft
2] <span> how many seconds does it take to reach the ground after first being thrown upward?
Here we solve for t intercept
</span>when d(t)=0
<span>thus</span>
0=-16t²+32t+88
<span>solving for t, we get:
t=1-</span>√13/2
or
<span>t=1+</span>√13/2
<span>
t=-1.55 or t=3.55 sec
Thus the answer is t=3.55 sec
</span>
Answer:
Question 11 would be D) 5x - 4y and Question 12 would be A) 7x + 6