Answer:
Refer to attached file below
Hope it helps..
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Answer:
B. n-octyl alcohol and 1-octene
Explanation:
Thin-layer chromatography (TLC) is a chromatography technique used to separate non-volatile mixtures. The principle is that different compounds in the sample mixture travel at different rates due to the differences in interactions with stationary phase and due to the differences in solubility in the solvent. The principal chemical property for separation using this technique is molecular polarity
You can intuit than hexadecane and octadecane don't have big polarity differences, also chlorobenzene and bromobenzene haven't.
An alcohol as n-octyl alcohol has different polarity than an alkene as 1-octene.
Thus, using thin layer chromatography is most easy to separate:
<em>B. n-octyl alcohol and 1-octene
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I hope it helps!
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Answer:
— 159.6°C
Explanation:
Data obtained from the question include:
V1 (initial volume) = 960L
T1 (initial temperature) = 38°C = 38 + 273 = 311K
V2 (final volume) = 350L
T2 (final temperature) =?
Since the pressure is constant, then Charles' law is in operation. Using the Charles' law equation V1/T1 = V2/T2, we can easily obtain the final temperature as follow:
V1/T1 = V2/T2
960/311 = 350/T2
Cross multiply to express in linear form.
960 x T2 = 311 x 350
Divide both side by 960
T2 = (311 x 350) /960
T2 = 113.4K
Now let us convert 113.4K to a number in celsius scale. This is illustrated below:
°C = K — 273
°C = 113.4 — 273
°C = — 159.6°C
Therefore, the container will have a volume of 350L at — 159.6°C
No, darker colors like purple and blue have higher wave frequency which transmit more energy.
The theoretical yield of acetate is 2607 g. The actual yield of acetate is 1066.8 g. The percentage yield of acetate is 41%.
If 1 mole of vinegar contains 6.02 x 10^23 particles
x moles of vinegar contains 9.02 x 10^24 particles
x = 1 mole x 9.02 x 10^24 /6.02 x 10^23
x = 15 moles of vinegar
The reaction is as follows;
2HC2H3O2 + CaCO3 -----> Ca(C2H3O2)2 + H2O + CO2
Since 2 moles of vinegar reacts with 1 mole of carbonate
x moles of vinegar reacts with 16.5 moles of carbonate
x = 2 moles x 16.5 moles/ 1 mole
x = 33 moles of vinegar
We can see that the vinegar is the reactant in excess hence the carbonate is the limiting reactant.
Theoretical yield = 16.5 moles x 158 g/mol = 2607 g
Actual yield = 6.35 moles x 158 g/mol = 1066.8 g
Percent yield = 1066.8 g/2607 g × 100/1
= 41%
Learn more: brainly.com/question/13440572?
