The reaction for combustion of hydrogen gas in the oxygen is as follows:
Here, oxygen is present in excess thus, hydrogen will be limiting reactant.
2 moles of hydrogen gives 2 moles of water vapor, thus, 1 mole will give 1 mole of water vapor.
The mass of hydrogen is 1.80 g and molar mass of 
is 2 g/mol converting mass into number of moles:
Thus, 0.9 mol of gives 0.9 mol of 
. Molar mass of is 18 g/mol, converting number of moles to mass,
m=n×M=0.9 mol× 18 g/mol=16.2 g
Therefore, mass of water vapor produced will be 16.2 g.
Answer:
Explanation:
To make a distinction in favor of or against a person or thing on basic or group, class or category, to which the person or thing(s) belong
Explanation:
I think the answer is B and A
Answer:
p orbital.
Explanation:
Valence electrons are the electrons in an atom holding the very last orbital which is used in chemical bonding with other elements. Their existence could define the chemical properties of that atom.
During the first energy in ionization of an N2 molecule the molecular orbital from which the electron could be extracted is the only one with the highest energy level. Nitrogen has its outermost orbital (p) containing three valence electrons. Each orbital is only half filled, and thus it is unstable Thus, the electron mission must have been removed from p orbital.
Answer:
When the concentration of F- exceeds 0.0109 M, BaF2 will precipitate.
Explanation:
Ba²⁺(aq) + 2 F⁻(aq) <----> BaF₂(s)
When BaF₂ precipitates, the Ksp relation is given by
Ksp = [Ba²⁺] [F⁻]²
[Ba²⁺] = 0.0144 M
[F⁻] = ?
Ksp = (1.7 × 10⁻⁶)
1.7 × 10⁻⁶ = (0.0144) [F⁻]²
[F⁻]² = (1.7 × 10⁻⁶)/0.0144 = 0.0001180555
[F⁻] = √0.0001180555 = 0.01086 M = 0.0109 M
Hope this Helps!!!
