Ask question

Ask question

All categories

3 years ago

7

A gas at 155 kilopascals and 25 °c has an initial volume of 1 liter the pressure of the gas increases to 605 kilopascals as the

temperature is raises ro 125°c what is the new volume?

1 answer:

KonstantinChe [14]3 years ago

3 0

i need to know the choices

You might be interested in

You and your friends decide to travel, on foot, to your favorite beach at the Jersey Shore. Your speed for the first part of the

Juli2301 [7.4K]

Answer:

Sorry dont know

Explanation:

8 0

3 years ago

Read 2 more answers

Molecule contains carbon, hydrogen and sulfur atoms. When a sample of 0.535g of this compound is burnt in oxygen, 1.119 g of CO2

OLga [1]

Answer:

The empirical formula is, C4H4S

Explanation:

Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles

Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g

Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles

Mass of hydrogen = 0.025 moles × 1 = 0.025 g

Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles

Mass of sulphur= 0.0064 moles ×32 = 0.2 g

Now we obtain the mole ratios by dividing through by the lowest ratio.

C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles

C4H4S

4 0

3 years ago

Drag each positive ion to bond it with a negative ion to form the neutral ionic compound indicated.

weeeeeb [17]

Answer:

1. NaCl

2. NH4F

3. MgO

4.LiCl

5. KI

6. CaO

Explanation:

In that order

8 0

2 years ago

A chemistry student weighs out 0.027 kg of an unknown solid compound X and adds it to 550. mL of distilled water at 30.° C. Afte

QveST [7]

Answer:

1. Yes

2.The solubility of X is 34.55g/L

Explanation:

Solubility of solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm $^{3}$ or 1 Litre of water.

From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved

= 0.019kg*1000 = 19g.

if 19g is required to saturate 550mL at 30°C,

then $\frac{19*1000}{550}$ will saturate 1L

= 34.545g will saturate 1Litre

The solubility thus is 34.55g/L

5 0

3 years ago

Where are human cells located (in living organisms)

defon

All inside and out in the human body

3 0

3 years ago