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Phantasy [73]
4 years ago
5

Solve this equation with a variable term on both sides:

Mathematics
2 answers:
Nastasia [14]4 years ago
8 0
5.1y + 21.3 = -0.3y-24.6
combine the variable smaller to bigger by adding 0.3y on each side
5.4y + 21.3= -24.6
Subtract 21.3
5.4y= -45.9
Then divide both sides by 5.4
Y=-8.5
serious [3.7K]4 years ago
7 0

Answer:

-8.5

Step-by-step explanation:

You might be interested in
A new Community Center is being built in Oak Valley. The perimeter of the rectangular playing field is 382 yards. The length of
vesna_86 [32]

Answer:

The width is 50 yards and the length is 141 yards.

Step-by-step explanation:

Let's call: L the length of the field and W the width of the field.

From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:

2L + 2W = 382

Because the perimeter of a rectangle is the sum of two times the length with two times the width.

Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:

L = 3W - 9

So, replacing this last equation on the first one and solving for W, we get:

2L + 2W = 382

2(3W - 9) + 2W = 382

6W -18 +2W = 382

8W - 18 = 382

8W = 382 + 18

8W = 400

W = 400/8

W = 50

Replacing W by 50 on the following equation, we get:

L = 3W - 9

L = 3(50) - 9

L = 141

So, the width of the rectangular field is 50 yards and the length is 141 yards.

3 0
3 years ago
Please help
tatuchka [14]
The independent variable is the # of hrs.
the dependent variable is # of gallons.
the slope is -125.
the y intercept is 13000
3000
7 0
3 years ago
Read 2 more answers
Ху Evaluate when x = 6 and y = 13. x + y
storchak [24]

EXPLANATION

When x=6 and y=13 x+y = 6 + 13 = 19

x + y = 19

7 0
1 year ago
5(x 1) − 8 = 5x(2 − 4)
svp [43]
Answer:
5 x (2 - 4)
5x-8= -10x
15x=8
x=8/15

Hope this helps!

3 0
4 years ago
You are running a race. The probability that you win is 3/5. What is the probability that you lose at most 2 out of your 6 races
Veronika [31]

Answer:

The probability that you lose at most 2 out of your 6 races is 0.54432.

Step-by-step explanation:

We are given that you are running a race. The probability that you win is 3/5.

There are total of 6 races.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 6 races

            r = number of success = at most 2 lost

            p = probability of success which in our question is probability that

                  you lose a race =  1 - (3/5) = 2/5 or 0.4

Let X = <u><em>Number of races lost </em></u>

So, X ~ Binom(n = 6, p = 0.40)

Now, the probability that you lose at most 2 out of your 6 races is given by = P(X \leq 2)

P(X \leq 2)  =  P(X = 0) + P(X = 1) + P(X = 2)

=  \binom{6}{0} \times 0.40^{0} \times (1-0.40)^{6-0} + \binom{6}{1} \times 0.40^{1} \times (1-0.40)^{6-1} + \binom{6}{2} \times 0.40^{2} \times (1-0.40)^{6-2}  

=  1 \times1 \times 0.60^{6} + 6 \times 0.40^{1} \times 0.60^{5} +15\times 0.40^{2} \times 0.60^{4}  

=  <u>0.54432</u>

7 0
3 years ago
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