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Alisiya [41]
3 years ago
10

A 1.85-m3 rigid tank initially contains air whose density is 1.18 kg/m3. The tank is connected to a high-pressure supply line th

rough a valve. The valve is opened, and air is allowed to enter the tank until the density in the tank rises to 5.30 kg/m3. Determine the mass of air that has entered the tank.
Physics
2 answers:
creativ13 [48]3 years ago
6 0

Answer:

we can conclude that mass of air that has entered the tank is 7.80 kg.

Explanation:

given data

volume = 1.85 m³

density 1 = 1.18 kg/m³

density 2 = 5.30 kg/m³

solution

we know that density is the mass present in per unit volume so that is

mass = density ×  volume    ........................1

here density is change so put here value in equation 1 we get

mass = (  5.30 - 1.18 ) kg/m³  × 1.85 m³  

solve it we get

mass = 7.807 kg

so we can conclude that mass of air that has entered the tank is 7.80 kg.

AVprozaik [17]3 years ago
5 0

Answer:

7.622 kg

Explanation:

Volume, V = 1.85 m³

initial density of air, d = 1.18 kg/m³

final density of air, d' = 5.3 kg/m³

initial mass of air, m = volume x initial density

m = 1.85 x 1.18 = 2.183 kg

final mass, m' = volume x final density

m' = 1.85 x 5.3 = 9.805 kg

mass of air entered, m' - m = 9.805 - 2.183 = 7.622 kg

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sladkih [1.3K]

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Answer:

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\displaystyle \text{average speed} = \frac{\text{total distance}}{\text{total time}}.

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The unit of the speeds in this question is meters per second, while the unit of distance is kilometers. Convert the unit of distance to meters:

560 \; \rm km = 560 \times 10^{3} \; \rm m = 5.6 \times 10^{5}\; \rm m.

1120 \; \rm km = 1120 \times 10^{3} \; \rm m = 1.12 \times 10^{6}\; \rm m.

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