It is called a warm front when a warm air mass moves into an area where a cold air mass is located based on the blanked sentence above. A warm front is a condition where a warm air mass is replacing a cold air in a place. The character of a warm front condition is an increasing in temperature of a place which is caused by the moving warm air mass<span>.</span>
Answer:
Move further apart
Explanation:
The negative charge on the rod repels the electrons on the cap thus they concentrate at the leaves causing an increase in the amount of charge at the leaves. Since like charges repel, the two leaves of the electroscope move further apart.
There is no list but I would say a landslide.
Answer:
The charge carried by the droplet is ![1.330\times10^{-19}\ C](https://tex.z-dn.net/?f=1.330%5Ctimes10%5E%7B-19%7D%5C%20C)
Explanation:
Given that,
Distance =8.4 cm
Time = 0.250 s
Suppose tiny droplets of oil acquire a small negative charge while dropping through a vacuum in an experiment. An electric field of magnitude
points straight down and if the mass of the droplet is ![2.93\times10^{-15} kg](https://tex.z-dn.net/?f=2.93%5Ctimes10%5E%7B-15%7D%20kg)
We need to calculate the acceleration
Using equation of motion
![s=ut+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
Put the value into the formula
![8.4\times10^{-2}=0+\dfrac{1}{2}\times a\times(0.250)^2](https://tex.z-dn.net/?f=8.4%5Ctimes10%5E%7B-2%7D%3D0%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%280.250%29%5E2)
![a=\dfrac{8.4\times10^{-2}\times2}{(0.250)^2}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B8.4%5Ctimes10%5E%7B-2%7D%5Ctimes2%7D%7B%280.250%29%5E2%7D)
![a=2.688\ m/s^2](https://tex.z-dn.net/?f=a%3D2.688%5C%20m%2Fs%5E2)
We need to calculate the charge carried by the droplet
Using formula of electric filed
![E=\dfrac{F}{q}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BF%7D%7Bq%7D)
![q=\dfrac{ma}{E}](https://tex.z-dn.net/?f=q%3D%5Cdfrac%7Bma%7D%7BE%7D)
Put the value into the formula
![q=\dfrac{2.93\times10^{-15}\times2.688}{5.92\times10^4}](https://tex.z-dn.net/?f=q%3D%5Cdfrac%7B2.93%5Ctimes10%5E%7B-15%7D%5Ctimes2.688%7D%7B5.92%5Ctimes10%5E4%7D)
![q=1.330\times10^{-19}\ C](https://tex.z-dn.net/?f=q%3D1.330%5Ctimes10%5E%7B-19%7D%5C%20C)
Hence, The charge carried by the droplet is ![1.330\times10^{-19}\ C](https://tex.z-dn.net/?f=1.330%5Ctimes10%5E%7B-19%7D%5C%20C)