Answer: 19
Step-by-step explanation:
Multiplying both sides of the equation by
gives that
.
1.41 is greater than 1.39
>
Answer:
miss girl-
Step-by-step explanation:
The answer is 5,600.00
Answer:
95 / 100 * 120 = 114 students
Thank you and please rate me as brainliest as it will help me to level up
Answer:
At 43.2°.
Step-by-step explanation:
To find the angle we need to use the following equation:

Where:
d: is the separation of the grating
m: is the order of the maximum
λ: is the wavelength
θ: is the angle
At the first-order maximum (m=1) at 20.0 degrees we have:

Now, to produce a second-order maximum (m=2) the angle must be:


Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.
I hope it helps you!