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sergiy2304 [10]
3 years ago
11

How many moles in 30.0 grams of h3po4

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
5 0
Molar mass H₃PO₄ = 98.0 g/mol

1 mole ----- 98.0 g
? mole ------ 30.0 g

moles = 30.0 * 1 / 98.0

= 0.306 moles

hope this helps!


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Answer:

320

Explanation:

8*8*5

8 0
3 years ago
If a plant produces 8.46 mol C6H12O6, how many moles of H2O are needed?
Ierofanga [76]

Answer:

50.76 mol H2O.

Explanation:

The photosynthesis follows the equation:

6CO2 + 6H2O ---> C6H12O6 + 6O2

This means that 6 mol of H2O are needed to obtain 1 mol of C6H12O6 (see the numbers that precedes every molecule to know how many mols are in game).

So we can say that:

1 mol C6H12O6 --------- 6 mol H2O

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8 0
3 years ago
A sample of xenon gas occupies a volume of 6.80 L at 52.0°C and 1.05 atm. If it is desired to increase the volume of the gas sam
Pavlova-9 [17]

Answer:

207.03°C

Explanation:

The following data were obtained from the question:

V1 (initial volume) = 6.80 L

T1 (initial temperature) = 52.0°C = 52 + 273 = 325K

P1 (initial pressure) = 1.05 atm

V2 (final volume) = 7.87 L

P2 (final pressure) = 1.34 atm

T2(final temperature) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final temperature of the gas sample can be obtained as follow:

P1V1/T1 = P2V2/T2

1.05 x 6.8/325 = 1.34 x 7.87/T2

Cross multiply to express in linear form as shown below:

1.05 x 6.8 x T2 = 325 x 1.34 x 7.87

Divide both side by 1.05 x 6.8

T2 = (325 x 1.34 x 7.87) /(1.05 x 6.8)

T2 = 480.03K

Now, let us convert 480.03K to a number in celsius scale. This is illustrated below:

°C = K - 273

°C = 480.03 - 273

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Therefore, the final temperature of the gas will be 207.03°C

5 0
3 years ago
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Answer:

95% Copper and 5% Zinc

Explanation:

Easy stuff read in the chemistry book...

3 0
3 years ago
What is the name of cells that have the ability to develop into different<br> kinds of cells?
ser-zykov [4K]

Answer:

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Explanation:

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