Question

A solid ball is rolling along a horizontal surface at 3.7 m/s when it encounters an upward

Answer 1

Answer:

h = 0.697 [m]  

Explanation:

To solve this problem we must use the energy conservation theorem, where it tells us that kinetic energy is converted to potential energy or vice versa.

$E_{kinet}=E_{pot}$

where:

Ekinet = kinetic energy [J]

Epot = potential energy [J]

$\frac{1}{2}*m*v^{2}=m*g*h\\0.5*(3.7)^{2} =9.81*h\\h =(6.845)/9.81\\h = 0.697 [m]$