A solid ball is rolling along a horizontal surface at 3.7 m/s when it encounters an upward

Physics

1 answer:

lys-0071 [83]3 years ago

4 0

Answer:

h = 0.697 [m]

Explanation:

To solve this problem we must use the energy conservation theorem, where it tells us that kinetic energy is converted to potential energy or vice versa.

$E_{kinet}=E_{pot}$

where:

Ekinet = kinetic energy [J]

Epot = potential energy [J]

$\frac{1}{2}*m*v^{2}=m*g*h\\0.5*(3.7)^{2} =9.81*h\\h =(6.845)/9.81\\h = 0.697 [m]$

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2. 26.2 m/s

3. increase

Explanation:

1. According to the law of energy conservation, when she jumps from the bridge to the point of maximum stretch, her potential energy would be converted to elastics energy. Her kinetic energy at both of those points are 0 as speed at those points are 0.

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