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anastassius [24]
3 years ago
11

The small piston of a hydraulic lift has a crosssectional area of 2.23 cm2 and the large piston 297 cm2 . What force must be app

lied to the small piston for the lift to raise a load of 2.4 kN? (In service stations, this force is usually exerted by compressed air.) Answer in units of N.
Physics
1 answer:
Lerok [7]3 years ago
8 0

Answer:

The force that must be applied to the small piston = 18.02 N.

Explanation:

Hydraulic Press: This is a device that produce a very large force to compress something e.g printing press.

From pascal's principle,

In an hydraulic press,

f/a = F/A......................... Equation 1

Where f = force applied to the small piston, a = area of the small piston, F = force required to lift the load/ force produced at the large piston. A = Area of the large piston.

Making f the subject of the equation above,

f = F×a/A.............................. Equation 2

Given: F = 2.4 kN = 2400 N, a = 2.23 cm², A = 297 cm².

Substituting into  equation 2

f = 2400(2.23)/297

f = 18.02 N.

Thus the force that must be applied to the small piston = 18.02 N.

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Inessa [10]

Answer:

15.8 seconds

Explanation:

Create an extended calculation to convert all the unit to what you need.

160 km      1000 m       1 hour         1 min

----------- x ------------- x -------------- x ----------   =  44.4 m/s

1 hour            1 km         60 min      60 sec

So 160km/hr is equal to 44.4m/s

Now you can figure out how many seconds it will take to go 700 meters.

44.4 m          

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1  sec

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x sec = 700m / 44.4 m/s

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3 years ago
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Elenna [48]
I'm not sure, I think it's option A.

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4 0
3 years ago
Two power lines run parallel for a distance of 222 m and are separated by a distance of 40.0 cm. if the current in each of the t
earnstyle [38]
1) Magnitude of the force:

The magnetic field generated by a current-carrying wire is
B= \frac{\mu_0I}{2 \pi r}
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Using I=135 A, the current flowing in each wire, we can calculate the magnetic field generated by each wire at distance 
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A similar procedure can be used on the wire on the left, finding that the force exerted on it is directed westwards, so the force between the two wires is repulsive.
6 0
3 years ago
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3 years ago
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