Answer:
The force that must be applied to the small piston = 18.02 N.
Explanation:
Hydraulic Press: This is a device that produce a very large force to compress something e.g printing press.
From pascal's principle,
In an hydraulic press,
f/a = F/A......................... Equation 1
Where f = force applied to the small piston, a = area of the small piston, F = force required to lift the load/ force produced at the large piston. A = Area of the large piston.
Making f the subject of the equation above,
f = F×a/A.............................. Equation 2
Given: F = 2.4 kN = 2400 N, a = 2.23 cm², A = 297 cm².
Substituting into equation 2
f = 2400(2.23)/297
f = 18.02 N.
Thus the force that must be applied to the small piston = 18.02 N.
