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2 years ago

How much energy is passed from one trophic level to the next

1 answer:

6 0

The amount of energy at each trophic level decreases as it moves through an ecosystem. As little as 10 percent of the energy at any trophic level is transferred to the next level; the rest is lost largely through metabolic processes as heat.

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The magnitude of the electric force between two protons is 2.30 10-26 n. how far apart are they?

SCORPION-xisa [38]

The electric force between two charge objects is calculated through the Coulomb's law.
F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m.

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2 years ago

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One charge is decreased to one-third of its original value, and a second charge is decreased to one-half of its original value.

Elanso [62]

I just had this question on my test, the answer is C.

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3 years ago

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A physics student spends part of her day walking between classes or for recreation, during which time she expends energy at an a

kondor19780726 [428]

RESULT: Twalk= 3.64 hr

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2 years ago

A ray diagram is shown.

alexandr402 [8]

Answer:

Explanation:

The purple and yellow rays from the same point on the object are shown converging at point Z, where the image will be.

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2 years ago

One object is thrown vertically upward with an initial velocity of 100 m/s and

gavmur [86]

We have that for the Question it can be said that The maximum height reached by the first object will be 100 times that of the other.

$(H_{max})_1=100*(H_{max})_2$

From the question we are told

One object is thrown vertically upward with an initial velocity of 100 m/s and another object with an initial velocity of 10 m/s. The maximum height reached by the first object will be

that of the other.

a. 10,000 times

b. none of these

c. 1000 times

d. 100 times

e. 10 times

Generally the equation for the velocity is mathematically given as

$v=\frac{d}{t}\\\\Where\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{(V_1)^2}{(v_2)^2}\\\\\frac{H_{max}_1}{H_{max}_2}=\frac{10000}{(10}\\\\$

$(H_{max})_1=100*(H_{max})_2$

Therefore

The maximum height reached by the first object will be 100 times that of the other.

$(H_{max})_1=100*(H_{max})_2$

For more information on this visit

brainly.com/question/23379286

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2 years ago