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julia-pushkina [17]
3 years ago
9

Are you the titantic bc i sure sunk in those eyes <33

Mathematics
2 answers:
elena55 [62]3 years ago
8 0
Are you wifi? Cause I connected to u ;)
FrozenT [24]3 years ago
5 0

Answer:

clever

Step-by-step explanation:

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HELP ME PLEASE <br> What is the value of z?
dybincka [34]

Answer:23

Step-by-step explanation:

7 0
3 years ago
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Solve the system of equations using any method. 2X – Y + Z = – 2, 6X + 3Y – 4Z = 8, – 3X + 2Y +3Z = – 6
krok68 [10]

Answer:

Z = - 2, Y = 0, X = 0

Step-by-step explanation:

2X – Y + Z = – 2

6X + 3Y – 4Z = 8

– 3X + 2Y +3Z = – 6

isolate "X" in the first equation

2X - Y + Z = - 2 => isolate "2X"

2X = - 2 - Z + Y => divide either side by 2

X = - 1 - Z/2 + Y/2

substitute this value of X in the second two equations (applying the substitution method here)

6(- 1 - Z/2 + Y/2) + 3Y - 4Z = 8,

6Y - 7Z - 6 = 8

- 3(- 1 - Z/2 + Y/2) + 2Y +3Z = - 6,

Y + 9Z + 6/2 = - 6

isolate Y in the second equation (6Y - 7Z - 6 = 8) and substitute in the third equation (Y + 9Z + 6/2 = - 6)

6Y - 7Z - 6 = 8 => isolate 6Y

6Y = 14 + 7Z => divide either side by 6

Y = 7Z + 14/6 => substitute in second equation

7Z + 14/6 + 9Z + 6/2 = - 6 => solve for Z

61Z + 50/12 = - 6, Z = - 2

substitute the value of Z into the equations "Y = 7Z + 14/6" and using the value of Y and Z, substitute into "X = - 1 - Z/2 + Y/2"

Y = (7(- 2) + 14)/6 = 0 / 6

= 0

X = - 1 - (- 2)/2 + 0/2 = - 1 - (-1) + 0

= - 1 + 1 + 0 = 0

6 0
3 years ago
4) You and a friend go out for lunch. Each of you paid $6.50 for the meal including a 6% sales tax.
noname [10]

Answer:6:11

Step-by-step explanation:

I hope this helps

8 0
3 years ago
Someone please help it’s for home work
kifflom [539]
1 6 dis 9/3 please please come out with the best way
8 0
3 years ago
Find the domain of ( (a+b/b) − (a/a+b))÷( (a+b/a) − (b/a+b) )
Alexandra [31]

Answer:

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, a=-b

Step-by-step explanation:

The domain refers to values for which the expression is defined.

This implies that, the denominators are not equal to zero.

(\frac{a + b}{b} -  \frac{a}{a + b}) \div ( \frac{a + b}{a} -  \frac{b}{a + b})

(\frac{(a + b)(a + b)-ab}{b(a + b)})\div(\frac{(a + b)(a + b)-ab}{a(a + b)})

\frac{(a + b)(a + b)-ab}{b(a + b)} \times\frac{a(a + b)}{(a + b)(a + b)-ab}

\implies \frac{a}{b}

Hence the domain is given as,b is such that b is a member of all real numbers,except b=0,a=0, and a=-b

7 0
3 years ago
Read 2 more answers
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