<u>Answer:</u> The correct option is b) 600
<u>Explanation:</u>
Molecules are formed when two atoms of same or different elements combine together.
Atoms are the smallest unit of matter that combines to form a compound.
For the given chemical compound, 
Given number of molecules = 300 molecules
In 1 mole of the given chemical compound, there are 2 atoms of carbon, 4 atoms of hydrogen and 2 atoms of oxygen
Number of atoms of oxygen = 
Number of atoms of oxygen = 
Hence, the correct option is b) 600
Answer:
percent yield = 40.6 %
Explanation:
The question asks to determine the percent yield, which can be defined as:
percent yield = 
where the actual yield is how much product was obtained, in this case 12.5 g of CCl₂F₂, and the theoretical yield is how much product could be obtained with the given reactants theoretically.
So we know already the actual yield, we need to <em>calculate the theoretical yield.</em>
First we need to <em>write the reaction chemical equation</em>:
CCl₄ + HF → CCl₂F₂ + HCl
and <em>balance the equation</em>:
CCl₄ + 2 HF → CCl₂F₂ + 2 HCl
In the equation we can see that <em>for every mol of CCl₄ we should get 1 mol of CCl₂F₂</em> (molar ratio 1:1). So if we <u>calculate the moles of CCl₄</u> in the given 39.2 g of CCl₄ we could know how many moles of CCl₂F₂ (assuming HF is in excess).
- Moles of CCl₄ = mass CCl₄ / molar mass CCl₄
- Molar Mass CCl₄ = 12.011 + 4 * 35.45 = 153.811 g/mol
- Moles of CCl₄ = 39.2 g / 153.811 g/mol = 0.2549 moles
From the molar ratio we know:
Moles of CCl₂F₂ = moles of CCl₄ = 0.2549 moles
Now we need to <u>convert these moles into grams</u> to get the theoretical yield of CCl₂F₂ in grams:
- mass CCl₂F₂ = moles CCl₂F₂ * molar mass CCl₂F₂
- Molar Mass CCl₂F₂ = 12.011 + 2 * 35.45 + 2 * 18.998 = 120.907 g/mol
- Mass CCl₂F₂ = 0.2549 moles * 120.907 g/mol = 30.81 g
- Theoretical yield CCl₂F₂ = 30.81 g
Percent yield = (12.5 g / 30.81 g) * 100 = 40.6 %
There are 20.8 moles of propanol
<h3>Further explanation </h3>
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
1.2 x 10⁵ molecules of propanol

Answer:
The answer to your question is P = 1.95 atm
Explanation:
Data
Pressure = P = ?
number of moles = n = 0.122
Volume = V = 1.5 l
Temperature = T = 20°C
Constant of ideal gases = 0.082 atm l/mol°K
Process
1.- Convert temperature to °K
T = 20 + 273
T = 293°K
2.- Write the formula of ideal gases
PV = nRT
-Solve for P
P = nRT/V
3.- Substitution
P = (0.122 x 0.082 x 293) / 1.5
4.- Simplification
P = 2.93 / 1.5
5.- Result
P = 1.95 atm