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3 years ago

Provide an explanation that is grounded in polarity that better explains why oil is not miscible in vinegar.

Chemistry

1 answer:

butalik [34]3 years ago

4 0

Explanation:

Vinegar is a sour liquid made up of acetic acid compounds. Oil is a complex non-polar chemical compound with a high amount of hydrogen and carbon in its structure.

Vinegar is a polar acid, although a weak one.
Generally, for a substance to mix with another one, they must be similar.
Solubility of compounds controls miscibility.
When two substances are miscible, they can be said to be soluble in one another.
In solubility, like substances dissolves like substances.
This implies that polar compounds will only dissolve polar compounds.
Non-polar compounds will only dissolve in non-polar solvents.
Since vinegar is polar and oil is non-polar, they will not dissolve one another.

Learn more:

Polarity brainly.com/question/2615067

#learnwithBrainly

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Which of the following possess the greatest concentration of hydroxide ions?

jek_recluse [69]

Answer : The correct option is (d) a solution of 0.10 M NaOH

Explanation :

(a) a solution of pH 3.0

First we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-3.0=11$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$11=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-11}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-11}M$

(b) a solution of 0.10 M $NH_3$

As we know that 1 mole of $NH_3$ is a weak base. So, in a solution it will not dissociates completely.

So, the $OH^-$ concentration will be less than 0.10 M

(c) a solution with a pOH of 12.

We have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$12=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-12}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-12}M$

(d) a solution of 0.10 M NaOH

As we know that $NaOH$ is a strong base. So, it dissociates to give $Na^+$ ion and $OH^-$ ion.

So, 0.10 M of $NaOH$ in a solution dissociates to give 0.10 M of $Na^+$ ion and 0.10 M of $OH^-$ ion.

Thus, the $OH^-$ concentration is, 0.10 M

(e) a $1\times 10^{-4}M$ solution of $HNO_2$

As we know that 1 mole of $HNO_2$ in a solution dissociates to give 1 mole of $H^+$ ion and 1 mole of $NO_2^-$ ion.

So, $1\times 10^{-4}M$ of $HNO_2$ in a solution dissociates to give $1\times 10^{-4}M$ of $H^+$ ion and $1\times 10^{-4}M$ of $NO_2^-$ ion.

The concentration of $H^+$ ion is $1\times 10^{-4}M$

First we have to calculate the pH.

$pH=-\log [H^+]$

$pH=-\log (1.0\times 10^{-4})$

$pH=4$

Now we have to calculate the pOH.

$pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-4=10$

Now we have to calculate the $OH^-$ concentration.

$pOH=-\log [OH^-]$

$10=-\log [OH^-]$

$[OH^-]=1.0\times 10^{-10}M$

Thus, the $OH^-$ concentration is, $1.0\times 10^{-10}M$

From this we conclude that, a solution of 0.10 M NaOH possess the greatest concentration of hydroxide ions.

Hence, the correct option is (d)

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3 years ago

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Al3+ is cation due to its positve charge
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4 years ago

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Answer:

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Explanation:

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3 years ago

What are the various ways in which an atom of an element can achieve the noble gas configuration ?

azamat

Answer:

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3 years ago

Match each statement with one of these terms.

skelet666 [1.2K]

Answer:

1 - e, 2 - k, 3 - a, 4 - i, 5 - b,

Explanation:

The ratio of the amount of analyte in the stationary phase to the amount in the mobile phase. --- Retention factor.

Time it takes after sample injection into the column for the analyte peak to appear as it exits the column. -- Retention time

The process of extracting a component that is adsorbed to a given material by use of an appropriate solvent system. -- Elution

Measure of chromatographic column efficiency. The greater its value, the more efficient the column. -- Theoretical plate number

Gas, liquid, or supercritical fluid used to transport the sample in chromatographic separations. -- Mobile phase

Immiscible and immobile, it is packed within a column or coated on a solid surface. -- Stationary phase

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3 years ago