Answer:
0.37 g
Explanation:
The molecular weight for Glycerol = 92
Number of Carbon atoms in glycerol (x) = 3
Molecular weight of the Biomass ( Klebsiella aerogenes )
=
=
= 26.1
From the molecular weight of the Biomass, we can deduce the Degree of reduction for the substrate(glycerol denoted as ) as follows:
= (4×1)+(1×1.73)-(2×0.43)-(3×0.24)
= 4.15
Given that the yield of the Biomass = 0.40 g
However;
C =
C =
C = 1.41 g
Now , the oxygen requirement can be calculated as:
=
=
= 2.1 g/mol
Hence, we can say that the needed oxygen = 2.1 g/mol of the substrate consumed.
Now converting it to mass terms; we have:
=
=
= 0.3652 g
≅ 0.37 g
∴ The oxygen requirement for this culture in mass terms = 0.37 g