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il63 [147K]
3 years ago
5

if a copper acetate hydrate, Cux(C2H3O2)y zH2O compound is found to contain 31.82% Copper, 59.14% acetate,and the remainder is w

ater. What is the empirical formula of this compound ?
Chemistry
1 answer:
marissa [1.9K]3 years ago
5 0
To make it easier, assume that we have a total of 100 g of a copper acetate hydrate. Hence, we have 31.82g of Cu, 59.14g of acetate and 9.18g of water. Know we will convert each of these masses to moles by using the atomic ie molecular masses of Cu, acetate, and water:

31.82/63.6= 0.5 mole of Cu
59.14/59= 1 mole of acetate
9.18/32= 0.51 mole of water

<span>Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the compound:
</span>
Cu = 0.5/05 = 1
acetate = 1 1/0.5= 2
water = 0.5/051 = 1

So, the empirical formula of the compound Cu(C2H3O2)2 × H2O 
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Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

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Moles of  Cl^-=Molarity\times {\text {Volume in L}}=0.240\times 0.2L=0.048moles

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b) Mass of SnCl_4= moles\times {\text {Molar mass}}=0.012mol\times 260.522g/mol=3.13g

Thus mass of  SnCl_4 Wenzhou use is 3.13 grams.

7 0
3 years ago
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