Answer:
water
Explanation:
because it's capable of dissolving more substances
Answer:
Hg, Tl, Pb, Bi.
Explanation:
The elements that are all in the same period are: Hg, Tl, Pb, Bi.
Kindly, find the attached image that show that all elements are in period 6.
Rb, Sr, La, Zr
:
All are in period 5 except La is in period 6.
Al, Ga, Si, P
:
All are in period 3 except Ga is in period 4.
N, O, Cl, Br:
N, and O are in period 2. While Cl is in period 3 and Br is in period 4.
Answer:
The final pressure of the gas is 370. kPa
Explanation:
Let's assume the gas inside cylinder behaves ideally.
As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-
![\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7B1%7DV_%7B1%7D%7D%7BT_%7B1%7D%7D%3D%5Cfrac%7BP_%7B2%7DV_%7B2%7D%7D%7BT_%7B2%7D%7D)
where
and
are initial and final pressure respectively.
and
are initial and final volume respectively.
and
are initial and final temperature in kelvin scale respectively.
Another assumption is necessary to solve this problem which is the process should be isothermal.
So
,
,
and ![V_{2}=4.40L](https://tex.z-dn.net/?f=V_%7B2%7D%3D4.40L)
Hence ![P_{2}=\frac{P_{1}V_{1}}{V_{2}}](https://tex.z-dn.net/?f=P_%7B2%7D%3D%5Cfrac%7BP_%7B1%7DV_%7B1%7D%7D%7BV_%7B2%7D%7D)
![\Rightarrow P_{2}=\frac{(163kPa)\times (10.0L)}{4.40L}](https://tex.z-dn.net/?f=%5CRightarrow%20P_%7B2%7D%3D%5Cfrac%7B%28163kPa%29%5Ctimes%20%2810.0L%29%7D%7B4.40L%7D)
![\Rightarrow P_{2}=370.kPa](https://tex.z-dn.net/?f=%5CRightarrow%20P_%7B2%7D%3D370.kPa)
So the final pressure of the gas is 370. kPa
Answer:
The answer would be Uranium-238
Explanation:
It's the only one that lasts longer than 40,000 years
Answer:
The answer to your question is 16 g
Explanation:
Data
Percent by mass = 8%
Mass of the solution = 200 g
Mass of solute = ?
Formula
Percent by mass = mass of solute / mass of solution x 100
- Solve for mass of solute
Mass of solute = Percent by mass x mass of solution / 100
- Substitution
Mass of solute = 8 x 200 / 100
- Simplification
Mass of solute = 1600 / 100
- Result
Mass of solute = 16 g