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Nataly [62]
3 years ago
14

Collin uses balloons to investigate static electricity. Which of the following BEST

Chemistry
2 answers:
vovangra [49]3 years ago
5 0

Answer:

The positive and negative electrons (or protons, don't really know) are opposites, so they attract each other, giving a whole new meaning to "Opposites attract."

Explanation:

RUDIKE [14]3 years ago
4 0
The correct answer is the second and third one eighr
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Using the name of the ionic compound, select the appropriate chemical formula. Use the periodic table
frutty [35]

The compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

<h3>What is an ionic compound?</h3>

An ionic compound is  compound that is composed of ions. We know that a poly atomic ion is an ion that contains more than one atom.

Looking at the options that have been provided, we know that the correct formula for the compound Ammonium Phosphate is (NH4)3PO4 while that of sodium acetate is NaC2H3O2.

Learn more about ionic compound:brainly.com/question/9167977

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2 years ago
The left-right inversion one word answer​
Vikki [24]

Answer:

Lateral Inversion

Explanation:

7 0
3 years ago
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mestny [16]

Answer:

8 X 100

Explanation:

3 0
3 years ago
Is a hydrogel a smart polymer/stimuli-responsive polmer?​
Vadim26 [7]
Polymer scientists have been trying to mimic this behavior by creating so called smart polymers. ... One of the most important classes of stimuli-responsive polymers used for controlled drug delivery is crosslinked polymer networks, e.g., hydrogels and microgels.
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8 0
3 years ago
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Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
cupoosta [38]

Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

3 0
4 years ago
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