Answer:
A(2,2)
Step-by-step explanation:
Let the vertex A has coordinates 
Vectors AB and AB' are perpendicular, then

Vectors AC and AC' are perpendicular, then

Now, solve the system of two equations:

Subtract these two equations:

Substitute it into the first equation:

Then

Rotation by 90° counterclockwise about A(2,2) gives image points B' and C' (see attached diagram)
Answer:
the cyclists rode at 35 mph
Step-by-step explanation:
Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then
distance= speed*time
since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :
time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train
thus denoting v as the speed of the cyclists :
7/8*L / v = L / 40 mph
v = 7/8 * 40 mph = 35 mph
v= 35 mph
thus the cyclists rode at 35 mph
The answer is 3x^2 + 19x - 12.
Answer:
<em>-9.5 + 6x ≥ 42.1 </em>
<em>6x ≥ 51.6</em>
x ≥ 8.6
Here, we can see that x is greater than or equal to 8.6. So, we can say that 8.6 is the lowest value of x
but we have 2 options with 8.6 as the lowest term, we can see that the brackets are different in the beginning
the '[' bracket tells us to include 8.6 in the values of x whereas the '(' bracket tells to exclude 8.6 from the possible values of x
since we know that x is greater than or equal to 8.6, we will use the '[' bracket
Hence, b is your answer
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