All categories

3 years ago

PLEASE PLEASE PLEASE HELP ME CHEM! DUE IN 10 MINS!! 20 POINTS (SPAM COMMENTS WILL BE BLOCKED) GIVING OUT BRAINLIEST

Chemistry

1 answer:

geniusboy [140]3 years ago

8 0

Answer:

Natrium oxide

4 Na atoms

2 O atoms

Fluoride

6 F atoms

Lithium sulfate

8 Li atoms

16 SO atoms

Calcium

2 Ca atoms

Aluminum hydroxide

2 Al atoms

3 OH atoms

Manganese sulfate

2 Mn atoms

12 SO atoms

Cuprum chloride

1 Cu atom

2 CI atoms

You might be interested in

An equal number of moles of KI (potassium iodide) and MgI2 (magnesium iodide) are dissolved in equal volumes of water.

SOVA2 [1]

<span> As we know that MgI2 (magnesium iodide) when dissociated it gives more ions than the KI so it has more boiling point as its boiling point is high it means that it boils more so it has low vapor pressure and freezing point

On the other hand as we know that KI dissociates into two ions so so it has high freezing and vapor pressure
hope it helps</span>

3 0

3 years ago

The noble gases are located in which column of the periodic table?A. 1B. 6C. 9D. 18

Vika [28.1K]

D IS THE ANSWER TO YOUR QUESTION

6 0

3 years ago

A ______ solution contains more dissolved solute than a saturated solution at the same temperature

NeTakaya

Answer:

i believe the answer is supersaturated

Explanation:

5 0

3 years ago

What are some physical means of separating something?

Alika [10]

Mixtures come in many forms and phases. Most of them can be separated, and the kind of separation method depends on the kind of mixture it is. Below are some common separation methods:

3 0

3 years ago

A helium filled ballon had a volume of 8.50 L on the ground at 20.0 C and a pressure of 750.0 Torr. After the ballon was release

Marrrta [24]

Answer:

$V_2=12.1L$

Explanation:

Hello!

In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:

$T_1=20+273=293K\\\\T_2=-40+273=233K$

Then, we obtain:

$V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L$

Best regards!

5 0

3 years ago