HI(aq)+NaOH(aq)→ what the final balanced chemical equation with the phases included
1 answer:
Answer:
Explanation:
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In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:
Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:
Which is also balanced as the number of atoms of all the elements is the same at both sides.
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Answer:
Explanation:
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In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:
Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:
Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:
Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:
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<u>Answer:</u> The moles of chlorine gas produced is 5.5 moles
<u>Explanation:</u>
We are given:
Moles of HCl = 11 moles
For the given chemical reaction:
By Stoichiometry of the reaction:
4 moles of HCl produces 2 moles of chlorine gas
So, 11 moles of HCl will be produced from of chlorine gas
Hence, the moles of chlorine gas produced is 5.5 moles