Answer:
0.0613 L
Explanation:
Given data
- Initial pressure (P₁): 1.00 atm
- Initial volume (V₁): 1.84 L
- Final pressure (P₂): 30.0 atm
Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 1.00 atm × 1.84 L / 30.0 atm
V₂ = 0.0613 L
198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.
After 17190 years, Carbon-14 will reach a mass of 15 grams.
Pi is your initial amount (120 grams)
0.5 as your exponential base represents your HALF life hence 0.5
t represents the time elapsed
c represents your given half life value of (5730)
P(t) represents the exponential function of your half life
120/2 =60
60/2 = 30
30 /2 = 15
As you can see above, 3 half lives of 5730 years EACH degraded the carbon-14 to 15 grams. You divide each number by two as it is a HALF life.
P(t)= Pi (0.5) ^t/c
P(17190) = 120 (0.5) ^17190/5730
P(17190) = 120 (0.5) ^3
P(17190) = 15 grams
So your answers should be 3 half lives or after 17190 years have elapsed!
Answer:
The equilibrium between the two forms of the gas is disturbed at high temperatures.
Answer: A) Water Explanation: Water molecules are polar molecules
