Radon is produced by uranium rocks underneath a house.
Answer:
c. 131 kPa
Explanation:
Hello!
In this case, since the relationship between volume and pressure is inversely proportional, based on the Boyle's law:
Considering that the standard pressure is 101.325 kPa, we can compute the final pressure as shown below:
Therefore, the answer is c. 131 kPa
.
Best regards!!
<u>Answer:</u> The boiling point of solution is 101.56°C
<u>Explanation:</u>
Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.
The equation used to calculate elevation in boiling point follows:
To calculate the elevation in boiling point, we use the equation:
Or,
where,
Boiling point of pure water = 100°C
i = Vant hoff factor = 1 (For non-electrolytes)
= molal boiling point elevation constant = 0.52°C/m.g
= Given mass of solute (urea) = 27.0 g
= Molar mass of solute (urea) = 60 g/mol
= Mass of solvent (water) = 150.0 g
Putting values in above equation, we get:
Hence, the boiling point of solution is 101.56°C
It will probably turned into a gumy
Answer:
Empirical formula: BH3
Molecular Formula: B2H6
Explanation:
To solve the exercise, we need to know how many boron atoms and how many hydrogen atoms the compound has. We know that of the total weight of the compound, 78.14% correspond to boron and 21.86% to hydrogen. As the weight of the compound is between 27 g and 28 g, using the above percentages we can solve that the compound has between 21.1 g and 21.8 g of boron, and between 5.9 g and 6.1 g of hydrogen:
100% _____ 27 g
78.14% _____ x = 78.14% * 27g / 100% = 21.1 g boron
100% ______27 g
21.86% ______ x = 21.86% * 27g / 100% = 5.9 g hydrogen
100% _____ 28 g
78.14% _____ x = 78.14% * 28g / 100% = 21.8 g boron
100% _____ 28g
21.86% _____ x = 21.86% * 28g / 100% = 6.1 g hydrogen
So, if the atomic weight of boron is 10.8 g, there must be two boron atoms in the compound that sum 21.6 g. The weight of hydrogen is 1 g, so the compound must have six hydrogen atoms.
The molecular formula represents the real amount of atoms that form a compound. Therefore, the molecular formula of the compound is B2H6.
The empirical formula is the minimum expression that represents the proportion of atoms in a compound. For example, ethane has 2 carbon atoms and 6 hydrogen atoms, so its molecular formula is C2H6, however, its empirical formula is CH3. Therefore, the empirical formula of the boron compound is BH3.
