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Simora [160]
3 years ago
13

How many grams of ammonium sulfate are needed to make a 0.25 M

Chemistry
1 answer:
Nadusha1986 [10]3 years ago
6 0
198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.
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bulgar [2K]

Answer: B

can u pls give me brain list?

8 0
3 years ago
Calculate the percentage by mass of lead in pbco3.
nignag [31]
Pb/pbco3*100
207/207+12+48
207/267*100
=77.53%
5 0
4 years ago
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Oxyacetylene torches produce such high temperature that they are often used to weld and cut metal. When 1.53 g of acetylene (C2H
hodyreva [135]

Answer: 4403kJ/mole

Explanation:

First we have to calculate the heat absorbed by bomb calorimeter  

Formula used :

q_b=c_b\times (T_{final}-T_{initial})

q_b = heat absorbed by calorimeter = ?

c_b = specific heat of = 10.69 kJ/K

T_{final} = final temperature = 44.688^oC=(273+44.688)K=317.688K

T_{initial} = initial temperature = 20.486^oC=(273+20.486)K=293.486K

q_b=10.69kJ/K\times (317.688-293.486)=258.7kJ

As heat absorbed by calorimeter is equal to the heat released by acetylene during combustion.

Thus 1.53 gram of acetylene releases heat of combustion = 258.7kJ

So, 26.04 g/mole of acetylene releases heat of combustion \frac{258.7}{1.53}\times 26.04=4403kJ/mole

Therefore, the heat of combustion of acetylene is, 4403kJ/mole

7 0
4 years ago
WILL GIVE BRAINLIEST!
goldenfox [79]

Answer:

A-Metals

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6 0
3 years ago
How many carbon atoms are there in a diamond (pure carbon) with a mass of "48" mg?
blagie [28]

Answer:

              3.47 × 10²³ C atoms

Solution:

Data Given:

                 Mass of Diamond  =  48 mg  =  0.048 g

                 M.Mass of Diamond  =  12.01 g.mol⁻¹ (as it is purely Carbon)

Step 1: Calculate Moles of Diamond as,

                 Moles  =  Mass ÷ M.Mass

Putting values,

                 Moles  =  0.048 g ÷ 12.01 g.mol⁻¹

                 Moles  =  0.576 mol

Step 2: Calculate number of Carbon atoms,

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Carbon atoms can be written as,

                 Moles  =  Number of C Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹

Solving for Number of C atoms,

                 Number of C atoms  =  Moles × 6.022 × 10²³ Atoms.mol⁻¹

Putting value of moles,

                 Number of C atoms  =  0.576 mol × 6.022 × 10²³ Atoms.mol⁻¹

                 Number of C atoms =  3.47 × 10²³ C atoms

7 0
3 years ago
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