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vekshin1
3 years ago
8

When jumping down from a table to the ground, it is helpful to bend your knees when you hit the ground because...

Physics
1 answer:
forsale [732]3 years ago
7 0

Answer:

This reduces the average force applied during the landing process/ or you can say it reduces the impact your body takes.

Explanation:

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Calculate the mass of a gas with a density of 0.0065 g/cm3 and volume of 260 cm3
Anuta_ua [19.1K]
\sf Density = \frac{mass}{volume }\\\\0.0065 =  \frac{mass}{260} \\\\{\boxed {\sf {mass =1.69 ~grams}}
6 0
3 years ago
Which sentence contains italicized words that are used as an infinitive phrase?
In-s [12.5K]
First, the infinitive phrase must contain the word "to", so the only options are A and D.

In D "to" is a preposition: it specifies the spacial relation: to the grocery store.

The infinitive phrase is "to go" and the answer is A.
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6 0
3 years ago
A fox is 7 meters from the base of a tree that is 15 m tall. A nest of owls is at the top of the tree. One of the owlets tosses
mamaluj [8]
Refer to the diagram shown below.

In this analysis, wind resistance is ignored, and g = 9.8 m/s².

The meat falls with zero vertical velocity, therefore the time, t, before the meat hits the ground is
\frac{1}{2}*(9.8 \, \frac{m}{s^{2}})*(t \, s)^{2} = (15 \, m) \\ t= \sqrt{ \frac{15}{4.9} }= 1.75 \, s

If the fox catches the meat before it hits the ground, then the fox should travel a horizontal distance d in the same time that the meat travels a horizontal distance (7 -d).
The meat travels a distance of 
7 - d = (1.2 m/s)*(1.75 s) = 2.1 m
or
d = 4.9 m

Let v =  velocity of the fox when it catches the meat.
If the acceleration of the fox is a m/s², then
v = 1.75a
Also,
d= \frac{1}{2} *(a \,  \frac{m}{s^{2}} )*(1.75 \, s)^{2} =  \frac{1}{2}( \frac{v}{1.75})^{2}*(1.75^{2})  \\ 4.9 = 0.875v^{2} \\ v^{2} = 5.6 \\ v = 2.366 \, m/s

Answer:  2.37 m/s  (nearest hundredth)



5 0
3 years ago
The Whirlpool galaxy is about 30 million light-years away. If you were in a spaceship that could travel at half of the speed of
Nataly_w [17]

Answer:

51.96 years

2) 30 million of years

Explanation:

First we must know the travel time of the ship seen from the earth. The spaceship travels at half the speed of light, this means that the amount of time the spacecraft must spend to travel the same distance is double compared to the light, that is 60 years.

Now due to the speed of the ship, we must take into account relativistic effects, such as time dilation, this is given by:

t'=\frac{t}{\sqrt{1-\frac{v^2}{c^2}}}

Where t is the time measured in the ship, t' is the time measured in the earth, inertially moving with velocity v.

Rewriting for t:

t=t'\sqrt{1-\frac{v^2}{c^2}}\\t=60\sqrt{1-\frac{(0.5c)^2}{c^2}}\\t=60\sqrt{1-0.5^2}\\t=51.96 years

This is the amount of time it would take you reach the Whirlpool galaxy in the spaceship.

2) a light year is a measure of distance, which indicates the kilometers that light travels in a year. Thus, the light emitted by Whirlpool galaxy takes 30 million of years reaches our planet.

6 0
3 years ago
Mass of a body is 210g and its density is 7.981g/cm^3 what will be its volume with regard to significant figures
aleksandrvk [35]

Density is mass per unit volume,

\rho=\dfrac mV

so to get the volume, divide the mass by the density,

V=\dfrac m\rho

So the volume is

\dfrac{210\,\mathrm g}{7.981\frac{\rm g}{\mathrm{cm}^3}}\approx26.312\,\mathrm{cm}^3\approx\boxed{26\,\mathrm{cm}^3}

3 0
3 years ago
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