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3 years ago

8

A book and a piece of paper the same size fall at different rates. How can you change the shape of the paper so that it will fal

l nearly as fast as the book?

1 answer:

Luda [366]3 years ago

3 0

Crumple the paper up to reduce air resistance

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3 years ago

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4 years ago

Read 2 more answers

What are the magnitude and direction of the net force on the third spider (S3) when it is resting at the origin

Alex

Complete Question

The complete question is shown on the first uploaded image

Answer:

The magnitude is $F_3 =0.62\ N$

Explanation:

From the question we are told that

The distance between the spiders is $a =0.59\ m$

The charge on the $S_1\ and\ S_3$ is $q_{1}=q_{3}=q =+4.9\mu \ C$

The charge on $S_2$ is $q_2 = 4.9\mu \ C$

Given that the charge are arranged in an equilateral triangle, it implies that the angle at each vertices of the triangle is 60°

Generally the magnitude of net force on $S_3$ is mathematically represented as

$F_3= F_{13} cos(60)+ F_{21} cos(60)$

So

$F_{13} =\frac{k* q^2 }{a^2}$

Here k is the columns constant with value $k = 9*10^9 \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.$

So

$F_{13}=\frac{9*10^9*((4.9*10^{-6})^2)}{0.59^2}$

=> $F_{13} = 0.62 \ N$

From the diagram we see that $F_{13}= F_{23} = 0.62\ N$

So

$F_3=0.62cos(60)+0.62cos(60)$

$F_3 =0.62\ N$

Now from the diagram the ls [tex]270^o[\tex] counterclockwise from x-axis

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4 years ago