What is the voltage drop across the 10.0 2 resistor?

Wants to slide his 430g water bottle precisely 12m to land inside a Bull's Eye! If the coefficient of kinetic friction between t

AleksAgata [21]

Answer:

Ff = u M g frictional force where u = .62

1/2 M v^2 kinetic energy of water bottle at release

Ff * d = 1/2 M v^2 = u M g d work to stop equals initial kinetic energy

v^2 = 2 u g d = 2 * .62 * 9.8 * 12 = 146 m^2 / s^2

v = 12.1 m/s

3 0

3 years ago

At one instant of time a rocket is traveling in outer space at 2500m/s and is exhausting fuel at a rate of 100 kg/s. If the spee

lawyer [7]

Thrust is a reaction force described quantitatively by Newton's third law. When a system expels or accelerates mass in one direction, the accelerated mass will cause a force of equal magnitude but opposite direction on that system. Mathematically can be written as,

$T = v\frac{dm}{dt}$

Here,

v = speed of the exhaust gases measured relative to the rocket.

$\frac{dm}{dt}$ = Rate of change of mass with respect to time

Our values are given as,

$v = 1500m/s$

$\frac{dm}{dt} = 100kg/s$

Replacing we have that

$T = 1500*100$

$\therefore T = 1.5*10^5N$

7 0

3 years ago

In 1600, Dr. William Gilbert coined the term “electrica,” a word that gave rise to our word electricity.

mrs_skeptik [129]

They recorded the first references to electrical effects, such as static electricity and lightning, over 2,500 years ago. It was not until 1600 that a man named Dr. William Gilbert coined the term “electrica,” a Latin word which describes the static charge that develops when certain materials are rubbed against amber.

3 0

3 years ago

PLEASE HELP. GRAVITY QUESTION, WRITTEN RESPONSE.

Rina8888 [55]

1) Forces acting on your body: force of gravity and normal reaction

2) Due to Newton's second law, N = mg

Explanation:

1)

When you sit on the computer, there are only two forces acting on you:

The force of gravity, acting downward, of magnitude $W=mg$ , where m is your mass and $g=9.8 m/s^2$ is the acceleration due to gravity, downward
The normal reaction exerted by the chair on you, $N$ , acting upward

Your body is in equilibrium (it doesn't move), this means that the two forces balance each other, therefore:

$N-mg=0\\N=mg$

2)

We can now apply Newton's second law of motion to this situation; this law states that the net force acting on a body is equal to the product between its mass and its acceleration. Mathematically,

$\sum F = ma$

where

$\sum F$ is the net force

m is the mass

a is the acceleration

In this situation, the net force is

$\sum F = N-mg$

So the equation becomes

$N-mg=ma$

However, we observe that your body is at rest; therefore, the acceleration is zero:

a = 0

And therefore,

$N-mg=0\\N=mg$

Learn more about forces:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0

4 years ago

Is gravitational pull strengthened by distance?

topjm [15]

I'm not sure but I think that if objects are closer (less distant), than the gravitational pull is stronger. I'm sorry if I couldn't really help I remember learning about this kind of.

5 0

3 years ago