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koban [17]
3 years ago
15

A car moving with a speed of 35 m/s sees a child standing in the

Physics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

2100 N

Explanation:

v = u + at \\ 0 = 35 + a(5) \\ a =  - 7m {s}^{ - 2}  \\ \\ net \: force \:  = ma \\  = (300)(7) \\  = 2100 \: newtons

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A coin 15.0 mm in diameter is placed 15.0 cm from a spherical mirror. The coin's image is 5.0 mm in diameter and is erect. Is th
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Answer:

15 cm

Explanation:

h_{o} = Diameter of the coin = 15 mm

h_{i} = Diameter of the image of coin =  5 mm

d_{o} = distance of the coin from mirror = 15 cm

d_{i} = distance of the image of coin from mirror = ?

Using the equation

\frac{d_{i}}{d_{o}} = \frac{- h_{i}}{h_{o}}

\frac{d_{i}}{15} = \frac{- (5)}{15}

d_{i} = - 5 cm

R = radius of curvature

Using the mirror equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{2}{R}

\frac{1}{15} + \frac{1}{- 5} = \frac{2}{R}

R = - 15 cm

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A 45-mH inductor is connected in series with a 60-Ω resistor through a 15-V dc power supply and a switch. If the switch is close
egoroff_w [7]

Answer:

The current is 0.248 A

Explanation:

Given that,

Inductor L= 45\times10^{3}\ H

Resistance R= 60\Omega

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Time t =7.0\times10^{-3}\ sec

We need to calculate the current

Using formula of current

I=\dfrac{V}{R}(1-e^{\dfrac{-R}{L}}t)

Where, V = voltage

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L = inductance

T = time

Put the value into the formula

I=\dfrac{15}{60}(1-e^{\dfrac{-60}{45\times10^{3}}}\times7\times10^{-3})

I=0.248\ A

Hence, The current is 0.248 A.

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