V = IR
I = current
R = resistance
Voltage = 100 * (3.44x 10^-4) = do the calculation
Hope this helps
Explanation:
The attached figure shows data for the cart speed, distance and time.
For low fan speed,
Distance, d = 500 cm
Time, t = 7.4 s
Average velocity,
![v=\dfrac{d}{t}\\\\v=\dfrac{500}{7.4}\\\\v=67.56\ cm/s](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7Bt%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7B500%7D%7B7.4%7D%5C%5C%5C%5Cv%3D67.56%5C%20cm%2Fs)
Acceleration,
![a=\dfrac{v}{t}\\\\a=\dfrac{67.56}{7.4}\\\\a=9.12\ cm/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%7D%7Bt%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B67.56%7D%7B7.4%7D%5C%5C%5C%5Ca%3D9.12%5C%20cm%2Fs%5E2)
For medium fan speed,
Distance, d = 500 cm
Time, t = 6.4 s
Average velocity,
![v=\dfrac{d}{t}\\\\v=\dfrac{500}{6.4}\\\\v=78.12\ cm/s](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7Bt%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7B500%7D%7B6.4%7D%5C%5C%5C%5Cv%3D78.12%5C%20cm%2Fs)
Acceleration,
![a=\dfrac{v}{t}\\\\a=\dfrac{78.12}{6.4}\\\\a=12.2\ cm/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%7D%7Bt%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B78.12%7D%7B6.4%7D%5C%5C%5C%5Ca%3D12.2%5C%20cm%2Fs%5E2)
For high fan speed,
Distance, d = 500 cm
Time, t = 5.6 s
Average velocity,
![v=\dfrac{d}{t}\\\\v=\dfrac{500}{5.6}\\\\v=89.28\ cm/s](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7Bd%7D%7Bt%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7B500%7D%7B5.6%7D%5C%5C%5C%5Cv%3D89.28%5C%20cm%2Fs)
Acceleration,
![a=\dfrac{v}{t}\\\\a=\dfrac{89.28}{5.6}\\\\a=15.94\ cm/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%7D%7Bt%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B89.28%7D%7B5.6%7D%5C%5C%5C%5Ca%3D15.94%5C%20cm%2Fs%5E2)
Hence, this is the required solution.
Answer:
r₁/r₂ = 1/2 = 0.5
Explanation:
The resistance of a wire is given by the following formula:
R = ρL/A
where,
R = Resistance of wire
ρ = resistivity of the material of wire
L = Length of wire
A = Cross-sectional area of wire = πr²
r = radius of wire
Therefore,
R = ρL/πr²
<u>FOR WIRE A</u>:
R₁ = ρ₁L₁/πr₁² -------- equation 1
<u>FOR WIRE B</u>:
R₂ = ρ₂L₂/πr₂² -------- equation 2
It is given that resistance of wire A is four times greater than the resistance of wire B.
R₁ = 4 R₂
using values from equation 1 and equation 2:
ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²
since, the material and length of both wires are same.
ρ₁ = ρ₂ = ρ
L₁ = L₂ = L
Therefore,
ρL/πr₁² = 4ρL/πr₂²
1/r₁² = 4/r₂²
r₁²/r₂² = 1/4
taking square root on both sides:
<u>r₁/r₂ = 1/2 = 0.5</u>