Answer:
Explanation:
y_1 = (3 mm) sin(x - 3t)
comparing it with standard wave equation
y = A sin( ωt-kx )
we see
ω = -3 , k = -1
velocity = ω / k
= 3
y_2 = (6 mm) sin(2x - t)
we see
ω = -1 , k = -2
velocity = ω / k
= .5
y_3 = (1 mm) sin(4x - t)
we see
ω = -1 , k = -4
velocity = ω / k
= .25
y_4 = (2 mm) sin(x - 2t)
we see
ω = -2 , k = -1
velocity = ω / k
= 2
So greatest velocity to lowest velocity
y_1 = (3 mm) sin(x - 3t) , y_4 = (2 mm) sin(x - 2t) ,y_2 = (6 mm) sin(2x - t) , y_3 = (1 mm) sin(4x - t)
b )
Given the mass per unit length of wire the same , velocity is proportional to
√ T , where T is tension
so in respect of tension in the wire same order will exist for highest to lowest tension .
Answer:
high accuracy low precision.
Explanation:
Answer:
462 nm
Explanation:
Given: width of the slit, d = 5.6 × 10⁻⁴ m
Distance of the screen, D = 4.0 m
Fringe width, β = 3.3 mm = 3.3 × 10⁻³ m
First dark fringe means n =1
Wavelength of the light, λ = ?
Theater=sin^-1(30/80)
theater=22
F=400gsin22=150N
F=ma
150=400a
a=0.375ms^-2
v^2-u^2=2as
v^2-0=2x0.375x80
v=7.75ms^-1
