Answer:
Thus, the velocity at the time of strike is same as the velocity at the time of projection.
Explanation:
Let a projectile is projected vertically upwards with a speed of u and reaches to the maximum height H.
At maximum height , the speed is zero and then the projective comes back on the ground.
Use the third equation of motion
Now let the velocity at the time of strike is v'.
Use third equation of motion, here initial velocity is zero.
Thus, the velocity at the time of strike is same as the velocity at the time of projection.
Explanation:
Initial speed of the incident water stream, u = 16 m/s
Final speed of the exiting water stream, v = -16 m/s
The mass of water per second that strikes the blade is 48.0 kg/s.
We need to find the magnitude of the average force exerted on the water by the blade. The force acting on an object is given by :
Here, 
So, the magnitude of the average force exerted on the water by the blade is 1536 N.
Answer:
The maximum velocity is 0.377 m/s
Explanation:
Please, the solution is in the Word file attached
Answer:
For the purposes of your question, we can think of speed and velocity as being the same thing. Therefore, the kinetic energy of an object is proportional to the square of its velocity (speed). In other words, If there is a twofold increase in speed, the kinetic energy will increase by a factor of four.
Explanation:
