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3 years ago

10

Suggest one reason why the bricklayer needs a higher energy diet than the computer operator

1 answer:

sashaice [31]3 years ago

7 0

Answer:

he needs more because he is doing more exercise this means he is working his body more and he needs more energy than someone he is sitting in an office. The computer operator would not need as much energy as the brick layer.

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An electron has a velocity of 1.50 km/s (in the positive x direction) and an acceleration of 2.00 ✕ 1012 m/s2 (in the positive z

olga nikolaevna [1]

Answer:

see explanation

Explanation:

Given that,

velocity of 1.50 km/s = 1.50 × 10³m/s

acceleration of 2.00 ✕ 1012 m/s2

electric field has a magnitude of strength of 18.0 N/C

$\bar F= q[\bar E + \bar V \times \bar B]\\\\\bar F = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]\\\\\\m \bar a = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]$

$9.1 \times 10^-^3^1 \times 2\times 10^1^2 \hat k=-1.6\times10^-^1^9 \hat k [18\hat k+ 1.5\times 10^3 \hat i \times (B_x \hat i +B_y \hat j +B_z \hat k)]$ $42.2 \times 10^-^1^9 \hat k = -2.4 \times 10^1^6B_y \hat k + 2.4 \times 10 ^1^6 \hat j B_z\\$

$B_x = undetermined$

$B_y = \frac{42.2 \times 10^-^1^9}{-2.4 \times 10^-^1^6} \\\\= - 0.0176 T$

$B_z = 0T$

8 0

4 years ago

Period vs string length

Galina-37 [17]

Trial 3 is the correct answer

8 0

3 years ago

An unpolarized beam of light with an intensity of 4000 W/m2 is incident on two ideal polarizing sheets. If the angle between the

erastova [34]

Answer:

The intensity is $I_2 = 1654 \ W/m^2$

Explanation:

From the question we are told that

The intensity of the unpolarized light is $I_o = 4000 \ W/m^2$

The angle between the ideal polarizing sheet is $\theta = 0.429 \ rad = 0.429 * 57.296 = 24.58^o$

Generally the intensity of light emerging from the first polarizer is mathematically represented as

$I_2 = \frac{I_o}{2}$

substituting values

$I_1 = \frac{4000}{2}$

$I_1 = 2000 \ W/m^2$

Then the intensity of incident light emerging from the second polarizer is mathematically represented by Malus law as

$I_2 = I_1 cos^2 (\theta )$

substituting values

$I_2 = 2000 * [cos (24.58)]^2$

$I_2 = 1654 \ W/m^2$

4 0

4 years ago

Please answer question B.

Flura [38]

Answer: 3.92

Explanation:

7 0

3 years ago

A soldier fires a gun and another boy at a distance of 1020 m hears the sound of firing the gun 33 seconds after seeing its smok

Komok [63]

Answer:

Speed of sound is 30.91m/s

Explanation:

Speed is given by:

Speed = distance travelled / time taken

Given:

Distance travelled = 1020m

Time taken = 33seconds

Speed = 1020m/33s

Speed = 30.91m/s

6 0

3 years ago

Read 2 more answers