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alexgriva [62]
3 years ago
10

Suggest one reason why the bricklayer needs a higher energy diet than the computer operator

Physics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

he needs more because he is doing more exercise this means he is working his body more and he needs more energy than someone he is sitting in an office. The computer operator would not need as much energy as the brick layer.

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Gravity on Jupiter is 25 m/s/s, what is the weight of a 12 kg object on Jupiter?
stiv31 [10]

Answer:

300 Newtons

Explanation:

Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.

The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have

Force = 12 × 25 = 300 Newtons or 300 N for short.

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2 years ago
How do you identify short and long term comets
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Atomic Mass Unit is the answer
6 0
2 years ago
A 9.0 V battery is connected across two resistors in series. If the resistors have resistances of and what is the voltage drop a
andreyandreev [35.5K]

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the answer to the question is known as D

4 0
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Suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen bu
ladessa [460]

Answer:

It can be concluded that the star is moving away from the observer.

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving  toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest for this case is 434 nm and 410 nm (\lambda_{0} = 434nm, \lambda_{0} = 410nm)

Redshift: \lambda_{measured}  >  \lambda_{0}

Blueshift: \lambda_{measured}  <  \lambda_{0}

Since, \lambda_{measured} (444nm) is greater than \lambda_{0} (434 nm) and \lambda_{measured} (420nm) is greater than \lambda_{0} (410 nm), it can be concluded that the star is moving away from the observer

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