Answer:
Cost of 18 pounds candy = $22.5
Cost of 10 pounds candy = $12.5
Cost of 1 pound of candies = $1.25
Step-by-step explanation:
6 pounds of butterscotch candies cost $7.50
⇔ 1 pound of same candy costs
$1.25
Now, we need to find the cost of 18 pounds of candy:
as, the cost of 6 pounds candy = $7.50
⇔ Cost of 6 x 3 = 18 pounds candy = $7.50 x 3 = $22.5
Cost of 10 pounds candy = 10 x (Cost of 1 pound candy)
= 10 x ($1.25) = $12.5
The unit rate for butterscotch candies = Cost of 1 pound of candies
= $1.25
Answer:
The roots are
<h3>
![x = - 3 + \frac{1}{3} i \: \: \: or \: \: \: x = - 3 - \frac{1}{3} i \\](https://tex.z-dn.net/?f=x%20%3D%20%20-%203%20%2B%20%20%5Cfrac%7B1%7D%7B3%7D%20%20i%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20x%20%3D%20%20-%203%20-%20%20%5Cfrac%7B1%7D%7B3%7D%20i%20%5C%5C%20)
</h3>
Step-by-step explanation:
9x² + 54x + 82 = 0
Using the quadratic formula
That's
<h3>
![x = \frac{ - b\pm \sqrt{ {b}^{2} - 4ac} }{2a}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B%20-%20b%5Cpm%20%5Csqrt%7B%20%7Bb%7D%5E%7B2%7D%20%20-%204ac%7D%20%7D%7B2a%7D%20)
</h3>
From the question
a = 9 , b = 54 , c = 82
Substitute the values into the above formula and solve
That's
<h3>
![x = \frac{ - 54\pm \sqrt{ {54}^{2} - 4(9)(82)} }{2(9)} \\ x = \frac{ - 54\pm \sqrt{2916 - 2952} }{18} \\ x = \frac{ - 54\pm \sqrt{ - 36} }{18} \\ x = \frac{ - 54\pm 6i}{18}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B%20-%2054%5Cpm%20%5Csqrt%7B%20%7B54%7D%5E%7B2%7D%20%20-%204%289%29%2882%29%7D%20%7D%7B2%289%29%7D%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B%20-%2054%5Cpm%20%5Csqrt%7B2916%20-%202952%7D%20%7D%7B18%7D%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B%20-%2054%5Cpm%20%5Csqrt%7B%20-%2036%7D%20%7D%7B18%7D%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B%20-%2054%5Cpm%206i%7D%7B18%7D%20)
</h3>
Separate the real and imaginary parts
That's
<h3>
![x = - \frac{54}{18} \pm \frac{6}{18} \: i \\ x = - 3\pm \frac{1}{3} i](https://tex.z-dn.net/?f=x%20%3D%20%20-%20%20%5Cfrac%7B54%7D%7B18%7D%20%5Cpm%20%5Cfrac%7B6%7D%7B18%7D%20%20%5C%3A%20i%20%5C%5C%20x%20%3D%20%20-%203%5Cpm%20%5Cfrac%7B1%7D%7B3%7D%20i)
</h3>
We have the final answer as
<h3>
![x = - 3 + \frac{1}{3} i \: \: \: or \: \: \: x = - 3 - \frac{1}{3} i \\](https://tex.z-dn.net/?f=x%20%3D%20%20-%203%20%2B%20%20%5Cfrac%7B1%7D%7B3%7D%20%20i%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20x%20%3D%20%20-%203%20-%20%20%5Cfrac%7B1%7D%7B3%7D%20i%20%5C%5C%20)
</h3>
Hope this helps you
Secxcotx=cscx
1/cos * cos/sin =cscx
cos/sincos=csc
1/sin=csc
Answer:
10 4 for question one
Step-by-step explanation:
I don't have one I just know how and I did this